Bi wiring?


I recently purchased a pair of Paradigm Studio 100 v1. I know the maximum recommended wattage for the speakers is 350 watts, but I am curious to know if they could be bi-wired with my denon receiver (125 watts) and my amp (300 watts). And if so, should I use the receiver for the highs and the amp for the lows??

Any feedback would be great, thanks!
gpetrons962
FYI: Technically, you are asking if you can "Bi-amp" your speakers, not merely "Bi-wire" them.

Having that much difference in power would probably yield more problems than it would be worth, IMHO. (And I imagine that the power reserves of a dedicated power amp are much greater than a receiver's power reserves, which would only make things worse.) And typically, a dedicated amp has a better sonic signature than a receiver, so you will probably notice a difference in quality.

However, that being said, you can try it and find out. (IMHO, having the reciever on the top end makes the most sense.)

Good Luck, (and let us know how it turns out if you decide to try it).
Correct, that would be bi-"amping", not bi-wiring. You would still need some way to control the outboard amp. Either level controls on the amp itself or an outboard crossover. Since the power ratings are so different, you'll need to balance them out.

Usually, biamping involves the same amps or running them through a crossover.
Since the power ratings are so different, you'll need to balance them out.

Since the voltage sensitivities are probably different, you will need to find a way to balance them. Power output capacity is irrelevant.

BTW, if the 300wpc amp is a good one, it will do just fine alone and without biamping. You do not need to have an amplifier capacity equal to the speaker's maximum rating.

Kal
use the amp that sounds the best imo

do not bother to biamp unless they sound very similar

if they are similar use the 300 watter on the bass

it remains to be seen if the sensitivity (I think the right word) of the amps is similar which would determine volume and compatability

have fun and be careful not to blow anything...
First, if you are using the preamp section of the receiver you can't bi-amp unless the receiver provides output jacks from its preamp section. Otherwise you would have no means of providing inputs to the separate power amp that are controlled by the receiver's volume control.

Second, bi-amping (or at least passive bi-amping) is unlikely to provide a significant increase in overall power delivery to the speakers. See the posts by me and by ElDartford in this thread. If done properly, with matching amps, bi-amping can provide some sonic benefits, but as was stated above that is not likely to occur using a receiver in combination with a dedicated power amp.

Third, I think that everyone is (correctly) saying the same thing about balancing the outputs of the two amps, but I would put it that what has to be matched are the voltage gains between the outputs of each amp and whatever point earlier in the signal path is common to both amps.

In other words, if you were connecting the preamp out jacks of the receiver (assuming it has them) to the power amp input jacks of the receiver and to the external amp, you would need to somehow match the gain of the external amp to the gain of the power amp section of the receiver. If you were connecting an external preamp to the external power amp and into input jacks of the receiver, you would have to match the power amp gain with the gain from those receiver input jacks to the outputs of the power amp section of the receiver. You could probably do that with the receiver's volume control, at the expense of the sonic effects of having the receiver's preamp section in the signal path in addition to the external preamp.

The gains can be calculated by taking the rated power output of each amp into 8 ohms; converting to voltage using the equation E = Square root of (P x R) (where P = rated max power into 8 ohms in watts, E = voltage in volts, and R = 8 ohms); and dividing by the input voltage that is specified to produce that rated output (the "sensitivity," as was stated). The resulting gain can be converted to db using the formula 20log(Vout/Vin).

Regards,
-- Al