No. The amp being used would see a load impedance equal to the speaker impedance in parallel with whatever output impedance the other amp has when it is turned off. That output impedance, in turn, is indeterminate, at least without detailed knowledge of the design. It may also vary unpredictably as a function of the signal level being applied to its output terminals at any instant of time by the amp that is being used.
Given that, both amps could conceivably be damaged -- the one being used due to excessive loading, and the one not being used due to application to its output terminals of voltages that are widely in excess of its internal dc voltage "rails," which would be zero in this situation.
And if both amps were ever inadvertently on at the same time, while one was playing music, the amp being used would be working into a near-zero ohm load impedance, corresponding to the output impedance of the other amp when it is powered up. That would result in very large amounts of current flowing, which could also damage both amps.
Regards,
-- Al
Given that, both amps could conceivably be damaged -- the one being used due to excessive loading, and the one not being used due to application to its output terminals of voltages that are widely in excess of its internal dc voltage "rails," which would be zero in this situation.
And if both amps were ever inadvertently on at the same time, while one was playing music, the amp being used would be working into a near-zero ohm load impedance, corresponding to the output impedance of the other amp when it is powered up. That would result in very large amounts of current flowing, which could also damage both amps.
Regards,
-- Al