Oh yes ... a quick follow-up to Joe.
Yes indeed, someone could easily order an arc that resulted in a 222.8 mm pivot to spindle distance.
Typically, you work backwards from effective length, but if you use John Ellison's wonderful spreadsheet and set the precision level to 4 decimal places, you can (using binary search techniques) derive any number you need in 5 or 6 tries.
Once you have an effective length, tell Yip (Mintlp) or Wally what you need and in 3 weeks (Yip) or ??? (Wally), it's in your mailbox.
It's all just computers and numbers and one number (222) is as good as another (222.8).
Cheers,
Thom @ Galibier
Yes indeed, someone could easily order an arc that resulted in a 222.8 mm pivot to spindle distance.
Typically, you work backwards from effective length, but if you use John Ellison's wonderful spreadsheet and set the precision level to 4 decimal places, you can (using binary search techniques) derive any number you need in 5 or 6 tries.
Once you have an effective length, tell Yip (Mintlp) or Wally what you need and in 3 weeks (Yip) or ??? (Wally), it's in your mailbox.
It's all just computers and numbers and one number (222) is as good as another (222.8).
Cheers,
Thom @ Galibier