MC LOADING & STEP UP DEVICE

Art Dudley was using "impedance ratio," in this case 933 to 1, as a round-about way of indicating the turns ratio (which is the square root of 933, since impedance is reflected between the two sides of the transformer in proportion to the square of the turns ratio).

Hence the primary and secondary coil impedances he refers to (3 ohms and 2800 ohms) differ by a factor of 933. But I'm not sure how either of those numbers are defined -- as dc resistance, or as impedance at some frequency with the other side of the transformer connected to some load, or what?

The reason for the 2.83 ohm vs. 3 ohm "coincidence" is that the 47K load impedance is an insignificant load in comparison to 2.8K, which in turn reflects back to the primary as 3 ohms, while 47K in parallel with 2.8K reflects back to the primary as 2.83 ohms.

However, it is incorrect to consider the 2.8K as being in parallel with the 47K. Within the range of its intended operating conditions (frequency and voltage), a transformer has (to a very close approximation) no impedance of its own. In Axel's example, the 18K that he assumed was in parallel with the 47K preamp impedance represented an external 18K resistor, not the transformer's secondary coil impedance.

Regards,
-- Al

Al, thank you for clarifying this:
>> In Axel's example, the 18K that he assumed was in parallel with the 47K preamp impedance represented an external 18K resistor, not the transformer's secondary coil impedance.<<<

The example aught to be clear, by looking at the basic calculation of parallel resistance: 47k input impedance parallel with an 18k load resistor on secondary.

It true, that the secondary coil DCR is ALSO reflected back into primary, again by dividing it by the square of the winding ratio.
B U T, it would be negligible in the case of my example and would be about 0.06ohm added to the calculated 13ohm of the example.
In the case of an FR XF-1 type M, (30dB) primary DCR = ~1.6 ohm, and secondary = ~ 60ohm (if I recall it correctly).

The secondary coil DCR is ALSO reflected back into primary, again by dividing it by the square of the winding ratio. B U T, it would be negligible in the case of my example and would be about 0.06ohm added to the calculated 13ohm of the example.

Yes, with the slight further clarification that the dc resistance of the secondary coil is reflected back into the primary by dividing it by the square of the winding ratio, in terms of its effects on the range of signal frequencies and voltages over which the transformer acts like a transformer. Which is why the 1.6 ohm and 60 ohm dc resistance numbers (dc being zero frequency) do not differ by a factor of 900 or so, in case anyone wonders.

Best regards,
-- Al

Wow, Axel thanks a million. Now I am just having a little trouble calculating. What is DCR?

Could we work through a case together so this crystallizes?

Data: Denon Au310 Step up, and 2 cartridges.

#1 Denon Au 310:

Winding wire ratio (pressure-up ratio) 1:10
Primary impedance 40ohms
Secondary impedance 4kohm
Frequency response 20Hz - 40kHz
Deflection (as opposed to 1kHz) Less than ±1dB
Magnetic shield Double
Chord length About 1.2m
Dimensions Width 51x height 53x depth of 181mm
Weight 0.65kg

#2 First Cartridge Supex Super 900
Output .2MV
Impedence 3.5 Ohm

#3 Second Cartridge Madrigal Carnegie one
Output Sensitivity: >0.26mV
Load Impedance: 30 to 50K ohms

So this is the data, now the calculations:

For the first cart:
winding ratio 1:10 of step up,
then Step #1 says-> since 1:10 = 20dB
then step #2 says-> 20*20*47kohm = ?
then step #3 says-> Well I need DCR, Don;t know what it is
now I am lost from here on.

Please help me fill in the blanks. Thanks again for helping me understand. It is greatly appreciated.

31.6 * 31.6 * 47k ohm = 47 ohm for a 30dB trannie

Please explain also, how you get this equality ?
=998.56*47kohms
=46932.32 kohms how is this = 47 ohm ?