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Phono rig capacitance

I have read up on LPFs (low pass filters) and corner frequencies. and found the following... this equation gives the -3db corner frequency: Fc = 1/(2*Pi*R*C), inductance is ignored but can be impleneted using the R-adjusted instead of R as SQRT(R*L), geometric average. Though the value may not be significant, which is why I usually see it omitted.

I am interested in:

1. how one computes the -0.5, or -1db or any db cut in frequency NOT just the 3db corner frequency.

2. How to compute the corner frequency for the cartridge to SUT, given the amount of capacitance in the interconnect. For the example I suppose using the all familiar cinemag 3440 makes sense and for the cart the denon 103.

3.Same as above, but to compute for the interconnect from the SUT to the preamp..

4. Same as above but compute for the interconnect from the preamp to the power amp.

5. And perhaps the same for loudspeakers as well.

The goal is to find a value that ensures there is no roll off taking place and to select a suitable wire for each interconnection in a phono based playback system using an MC cartridge->SUT->Pre->Power.

I know, less capactiance blah blah blah, buy a 4 thousand dollar cable blah blah blah is the usual answer, but I am looking for a more scientific and technical approach to selecting wires that are in the ballpark of what makes sense based on well understood engineering principles.

I know that there are several members with advanced degrees in electrical engineering or are technically apt (Almrag, Atma, Raph etc...) and I am hoping that one of you can find the time to chime in please.

Thanks guys, looking forward to hearing your take!
dfel
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almarg
9,670 posts
 
Dfel, what Jonathan said is of course correct. The cartridge does not see the capacitance on the secondary side of the SUT divided by 100 (the square of the turns ratio we are assuming). Since the SUT transforms impedance in proportion to the square of the turns ratio, the cartridge sees the **capacitive reactance** that is on the secondary side divided by 100.

Since as you indicated earlier Xc = 1/(2*pi*f*C), capacitive reactance is inversely proportional to capacitance, and so the cartridge sees the capacitance on the secondary side **multiplied** by 100.

This is all based on an assumption of ideal behavior by the SUT, of course. No transformer will behave in a completely ideal manner, due to many factors. So all of this is of course just an approximation, but it is a good approximation for practical purposes.

Regards,
-- Al
jcarr
382 posts
 
Dear Dfel: Here is an alternative way to envision what a SUT does.

As a passive device, a SUT cannot create more energy. Its voltage amplification abilities are limited to converting the MC cartridge's output current into voltage. But since a SUT cannot create more energy, the cartridge signal current that gets converted into signal voltage is no longer available at the SUT output.

And since current is what charges and discharges capacitance, inserting a SUT between MC cartridge and phono stage reduces the cartridge's ability to charge and discharge whatever capacitance is present on the SUT secondaries by the square of the primary-secondary turns ratio.

hth, jonathan carr
dfel OP
62 posts
 
I can say I only partly understand, I will have to learn a little more to fully wrap my head around how it works. However, for now:

I tried modeling the transformer, not sure why I am running into problems here. I will try to post the image later maybe you can offer some guidance on the schematic/model for simulation. again ,much appreciated thanks guys!
dfel OP
62 posts
 
Hi guys, I have been having a lot of trouble modeling this correctly with the SUT in the mix. I am sure I am making some silly mistakes but I can't find them. Here is a link to the image of the simulation + circuit model. I tried to follow the model from the snippets I could find online to the paper by J carr, I would love to read the whole paper one day..please PM me since I cant PM you Jcarr.

For the earlier simulations it was easy to lean on the Hagerman article and simply copy the circuit and play with the parameters. But, in this case it is not so simple, and I would appreciate some help. Thanks.

http://s27.postimg.org/aage8hg2/Attempt_at_Circuit_Model.png

I am assuming the same cart specs from the paper, and using the specs for the mogami 2549 wire, 0.022 Ohms/foot, 26pf/foot, and 0.72uH. I used a 1:10 Step up ratio for the SUT.

Please tell me how if I have made a mistake here ( I am sure I have), and how to correct it as I am interested in seeing this display something meaningful. Please be gentle with the commentary as I am a rookie and know nothing about Electrical Engineering. Thanks again.
dfel OP
62 posts
 
Link was not working lets try again:

http://s27.postimg.org/aage8hg2r/Attempt_at_Circuit_Model.png

http://postimg.org/image/6e32chv33

http://postimg.org/image/6e32chv33/full

Hopefully one of those links works.
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