Running Benchmark AHB2 in bridged mode and 4 Ohm Speaker


Does running this amp in bridge mode mean each channel will see half the impedance i.e 2 Ohm each when connected to a 4 Ohm speaker.  If so will this cause a problem when the speaker dips to 3 or 2 ohms?. 

Anyone running Benchmark AHB2 in bridged mode with low impedance speakers?. 
geek101
What would have been good to see is this simulated speakers load graph which is "non bridged" vs the bridged on the same simulated speaker load graph.

Non bridged is good showing good current ability.
https://www.stereophile.com/images/1115BAHB2fig01.jpg

I would bet looking at the wattage's I posted before, the "wavy black line" in the graph above, would be far more wavy with the bridged than the non bridged.
But were’re never ever going to see that with the same test equipment now.

Cheers George
The Stereophile graph referenced above is done at 2.83V which is equivalent to 1W/8ohms and 2W/4ohms. 
Obviously, whether bridged or in stereo mode it won't be effected by any insinuated current limitation.
What will effect the simulated speaker load is higher output impedance - which is doubled with the bridged amp - but because its already usefully low this won't make a substantial (read audible) difference.
It certainly won't turn the bridged AHB2 into a tone control - which is a ridiculous exaggeration - especially in comparison to any tube amp or many other SS amps for that matter. 
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An amp that can put 480 watts into 4 ohms can put 240 watts into 8 ohms so it can double from 240 to 480.  You can just think of it as an amp that puts 240 watts into 8 ohms and doubles into 4.  Its ability to put more than 240 watts into 8 ohms isn't that relevant.  Regardless of how you think about it, the amp delivers more current in bridged more.  At any given volume the bridged amp will have better current capability.  At 100 watts into 8 ohms it can double to 200 into 4 and again to 400 into 2 ohms since we know it can deliver at least 480 watts total.  A speaker is a passive component so obviously increasing the power delivered to it increases the current.  How else could it be?