Al, you are correct. I need to take into account the SUT with a 100 ohms setting on my phono preamp. But if you run the calculations as if loading on the secondary side, doesnt look like I will be able to do it - Id have to increase load, and that is a lot harder.
SUTs and Resistive Loading Questions
Hello, I have a few questions about SUTs and adding parallel resistors to reduce the load impedance.
I have a SUT with a 1:15 turns ratio. As we know, the load for a 1:15 SUT through a MM/47,000 phono preamp would be: 47,000/15/15 = 209 ohms.
However, I want a load impedance of 100 ohms for the MC cart I'm using. To calculate the value of the resistor I need to add in parallel to do so:
100 ohms = Z/15/15 for a SUT with a 1:15 turns ratio. Solving for Z = 22,500 ohms.
Resistor Value Needed = 1/((1/22,500 ohms) - (1/47,000 ohms)) = 43,164 ohms.
So now, my questions...
If my phono preamp has a 100 ohms load setting, can I use that (instead of the 47,000 ohms setting and the above calculations for adding parallel resistor) to essentially get the 100 ohms load impedance I want?
Also, is there any difference in damping using the first method versus the second method? I would think not, but not completely sure.
Thanks for your insight.
I have a SUT with a 1:15 turns ratio. As we know, the load for a 1:15 SUT through a MM/47,000 phono preamp would be: 47,000/15/15 = 209 ohms.
However, I want a load impedance of 100 ohms for the MC cart I'm using. To calculate the value of the resistor I need to add in parallel to do so:
100 ohms = Z/15/15 for a SUT with a 1:15 turns ratio. Solving for Z = 22,500 ohms.
Resistor Value Needed = 1/((1/22,500 ohms) - (1/47,000 ohms)) = 43,164 ohms.
So now, my questions...
If my phono preamp has a 100 ohms load setting, can I use that (instead of the 47,000 ohms setting and the above calculations for adding parallel resistor) to essentially get the 100 ohms load impedance I want?
Also, is there any difference in damping using the first method versus the second method? I would think not, but not completely sure.
Thanks for your insight.
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- 15 posts total
- 15 posts total