Driver efficiency vs. overall speaker efficiency


If a speaker uses a driver that has an efficiency of, let's say 87.5db/2.83V/m, then theoretically the speaker can never have an efficiency of greater than 97.5db?
andy2
Satch...Efficiency is stated as dB per VOLT (not current). Of course the current will be more with a 4 ohm load, but that's the power amp's problem.
Satch:

I'm not an expert,so allow me to quote my source:

http://www.northcreekmusic.com

If you link through to the page that describes their rhythm speaker,in the fine print,it talks about an mtm set-up and its effects.(It's the paragraph labeled "Sensitivity and Impedance".)
High-efficiency speakers-

Are they just going to give more sound-per watt, or will they also communiate more texture (micro-dynamics?) of the sound, along with the extra dB?
Here we go again. One thing we modern folk oft do is to use the WRONG terminology. 'Efficiency' is different than 'sensitivity'. Speaker-system efficiency normally is measured 1 meter from the speaker/driver when driven with exactly 1 watt of power measured into the speaker's rated impedance. IOW, a '4-ohm' speaker system's output is measured while being driven by TWO volts into 4 ohms (which equals ONE WATT). Decades ago, with the increasing popularity of solidstate amps*, the audio industry started publishing sensitivity ratings, and not all of them do it correctly.

Sensitivity is measured with a signal created by driving an 8-Ohm load resistor with 2.83 volts. That does happen to be 1 watt into 8 ohms, but it's not 1 watt into 6 or 4 or 3 or 2 ohms. The correct way to state this is 'sensitivity at 1M using 2.83v. into 8 Ohms' or something like that. And BTW, it's not PER meter, it's at 1 meter.

*--Solidstate amplifiers are constant-voltage devices and not constant-current devices are as most tubed amps. That is, because a SS amp's output impedance is so low, it will maintain its output voltage into decreasing loads until it reaches its maximum current output. A tubed amp generally will NOT increase its current output much as the load impedance decreases.
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