You are tiring me out Mr. djones51.
Consider this answer to be the last !
Haven’t seen any explanations of your source for the AWG table or the errores calc.
A 105 for DF is not that much of a DF. But as this is what it is, let’s do it:
105 DF = 8/105 = 0.076 Ohms as Ro.
If using a #16 awg cable (6 ft) = 0.048 ohms as R cable.
Add the DF (Ro) and the cable (R):
0.076 + 0.048 = 0.124 ohms
0.124 ohms equals to a combined DF of 8 / 0.124 = 64
So, by you using a #16 you are losing 40% of the original DF of that Amp (105).
Is 40% still insignificant?
But why 105?
Do it with a DF of 400 ! (there are guys gere with Amps of 800 and even 4000)
400 DF = 8 / 400 = 0.02 ohms.
With a # 16 awg you lose 70% and so on...
(you claim its insignificant, so I take the liberty of using a #16 awg) .
Is that significant enough for you?
Most of cables out there are of #12 awg, for the convenience of making them,
rather of: being significant for the task...
Would you like that attitude when sitting on the dentist chair, or at a bypass surgery? That would be a first.
With a #12 awg, you about to lose 50%!
I can understand that you can cut your loss in advance, if you go to gamble Vegas or buy some shares.
It's a game with chances to WIN but also to LOSE.
Is 50% loss on the sound is insignificant for you?
Sticking to your thin cables,
you only lose! (unfair)
No WIN !!!