invalid,
Of course you can get more power. It is ludicrous to think otherwise. An amp is like (bit of an exaggeration to get the point across) your mains amplifying a 60 Hz signal. If you connect a 120 ohm load to mains, you will get 120 watts, if you connect a 60 ohm load, you will get 240 watts, if you connect a 30 ohm load, you will get 480 watts, etc, until you blow your fuse.
AS LONG AS YOUR MAINS DOES NOT COLLAPSE AND YOU DO NOT EXCEED YOUR CURRENT LIMIT, you WILL get more power. It is virtually the same in amps. It is like supplying a 60 hz continuous signal. As long as the power supply can supply the needed current, it will keep on supplying more power. The limitation with amps is the heatsink/output stage design (transistor current limits), the maximum internal impedance and its stability at different frequencies. The ideal amp (again, an asymptotic exaggeration) will even handle a short cirtcuit across its speaker where the current will be limited by only the internal impedance of the output stage. This obviously will blow the transistors but you get my point.
Of course you can get more power. It is ludicrous to think otherwise. An amp is like (bit of an exaggeration to get the point across) your mains amplifying a 60 Hz signal. If you connect a 120 ohm load to mains, you will get 120 watts, if you connect a 60 ohm load, you will get 240 watts, if you connect a 30 ohm load, you will get 480 watts, etc, until you blow your fuse.
AS LONG AS YOUR MAINS DOES NOT COLLAPSE AND YOU DO NOT EXCEED YOUR CURRENT LIMIT, you WILL get more power. It is virtually the same in amps. It is like supplying a 60 hz continuous signal. As long as the power supply can supply the needed current, it will keep on supplying more power. The limitation with amps is the heatsink/output stage design (transistor current limits), the maximum internal impedance and its stability at different frequencies. The ideal amp (again, an asymptotic exaggeration) will even handle a short cirtcuit across its speaker where the current will be limited by only the internal impedance of the output stage. This obviously will blow the transistors but you get my point.