Hi Wyn,
Yes, that is of interest. And I agree with your math, of course, while having two comments:
First, I’m not sure that "back EMF" would be the best terminology to apply to what you are calculating, or the best way of considering it (see the next paragraph for my perspective on that). As you no doubt realize, that term is commonly used in the context of speakers, where a signal is applied by an external source, and back EMF is generated by the speaker as motion of a driver coil in its surrounding magnetic field continues beyond what is called for by the signal. In this case, of course, it is motion of the cartridge’s coil which generates the signal, as opposed to coil motion that occurs in response to an applied signal.
Second, I believe that what your calculation reflects is simply the high frequency rolloff which occurs as a result of the interaction of cartridge inductance and load resistance, putting aside the effects of capacitance. In your example, 2 x pi x f x L (i.e., inductive reactance) would become equal to the 100 ohm load impedance at a frequency of about 1.35 MHz, resulting in a 3 db bandwidth equal to that amount. So the error you are calculating, if indeed it can be considered to be an error, would seem to be insignificant at audible frequencies.
Regards,
-- Al
Yes, that is of interest. And I agree with your math, of course, while having two comments:
First, I’m not sure that "back EMF" would be the best terminology to apply to what you are calculating, or the best way of considering it (see the next paragraph for my perspective on that). As you no doubt realize, that term is commonly used in the context of speakers, where a signal is applied by an external source, and back EMF is generated by the speaker as motion of a driver coil in its surrounding magnetic field continues beyond what is called for by the signal. In this case, of course, it is motion of the cartridge’s coil which generates the signal, as opposed to coil motion that occurs in response to an applied signal.
Second, I believe that what your calculation reflects is simply the high frequency rolloff which occurs as a result of the interaction of cartridge inductance and load resistance, putting aside the effects of capacitance. In your example, 2 x pi x f x L (i.e., inductive reactance) would become equal to the 100 ohm load impedance at a frequency of about 1.35 MHz, resulting in a 3 db bandwidth equal to that amount. So the error you are calculating, if indeed it can be considered to be an error, would seem to be insignificant at audible frequencies.
Regards,
-- Al