Watts and power

Thank you for your reply @audiozenology

Optimize,

• P = v * I
• P = v^2 / R
• P = i^2 * R
• 
  

If you know P and R, then you can calculate I and V.

But I could not really wrap my head around WHY the correct formulas could work to calculate I and V on a amplifier output.

Because that would suggest that ALL amplifiers with different operations classes, types of FET and wiring singel ended/Push pull. Gives the SAME constant and relationships so only from wattage and resistance you can get the I and V.

That is something I don’t believe is true at all!

And I think I found the missing link.. Why you think that we kan use those formulas on the output power for a amplifier!

The formulas above only works on:
Single Phase OR Three Phase Delta
https://www.chromalox.com/Resources%20and%20Support/calculators/ohms-law

That is logical when you measure on a constant like between different phase conductors in your home and I believe it is not applicable on the any given amplifier output.

But I can be wrong maybe any other more gifted than I could share a light on the subject. :)

Optimize, amplifier power tests, right or wrong are made into constant resistance loads. The equations I posted are simple extensions of ohms law. All that is required is to use RMS values. They work.


With inductive and capacitive loads there may be other thermal limits placed on the available power, at least with non switching amplifiers.

audiozenology"amplifier power tests, right or wrong are made into constant resistance loads"

This is true of course when amateurs, hobbyists, and inexperienced users conduct such tests but when performed by experts, engineers, and designers a much more thorough, complete, and extensive composition of tests is undertaken to accurately assess how a Music Reproduction System component will perform in real-world conditions by the end user.

Because that would suggest that ALL amplifiers with different operations classes, types of FET and wiring singel ended/Push pull. Gives the SAME constant and relationships so only from wattage and resistance you can get the I and V.

This is correct even though you don't believe it. If a given amp makes a certain power into a certain load, then it will be making exactly the same voltage and current as any other amplifier that can do the same thing.

What might be tripping you up here is output impedance plays a role. If the amp has a higher output impedance, more of its output power will be dissipated in the output section itself rather than the load when presented with a low impedance load. Since no loudspeaker is a flat impedance from top to bottom, this means that different amps can sound different, even though at certain impedances of the speaker they might all make the same power.


To further muddy the waters, not all speakers are meant to be driven by amps with a super low output impedance, while others are. For more on this see:
http://www.atma-sphere.com/Resources/Paradigms_in_Amplifier_Design.php

Oh come on Clearthink. You can do better than that. I am not sure that rant is even worthy of inclusion in my book, "Clearthink's Practical book of Impractical Rants". I have come to expect much more of you.