Jameswei--
The PrimaLuna One's input impedance is 100k ohms, Input sensitivity 300mV. Viz.
Description: Single-box line-level tube preamplifier and push-pull tube power amplifier. Tube complement: two each 12AX7A, 12AU7, EL34. Inputs: 4 single-ended. Output power: 35Wpc into 8 ohms (15.4dBW). Voltage gain: 20dB. Output impedance: 4 or 8 ohms. Frequency response: 20Hz30kHz, ±0.5dB. Input impedance: 100k ohms. Input sensitivity: 300mV.
The CL-15's output impedance is 50 ohms (usable into passive controller).
Does this seem doable? The P'Luna's impedance is listed in kilo-ohms, while the CL-15's impedance is given in ohms. My newbie's provisional conclusion, then, is that there should be plenty enough of difference still.
However, one logical question--which component's impedance will be cut by half? Your language suggests it will be the P'Luna's, but my beginner's mind says it will be the CL-15's. If this is the case, then there may be too huge a difference created by the double hook-up, dropping the CL-15's output impedance by so much that the signal coming in from at least one of the outputs of the CL-15 will look to the P'Luna like a short. This happened with the ECI 3 amp already, although I realize I'm speaking hypothetically with regard to the P'Luna. I still haven't tried it.
The PrimaLuna One's input impedance is 100k ohms, Input sensitivity 300mV. Viz.
Description: Single-box line-level tube preamplifier and push-pull tube power amplifier. Tube complement: two each 12AX7A, 12AU7, EL34. Inputs: 4 single-ended. Output power: 35Wpc into 8 ohms (15.4dBW). Voltage gain: 20dB. Output impedance: 4 or 8 ohms. Frequency response: 20Hz30kHz, ±0.5dB. Input impedance: 100k ohms. Input sensitivity: 300mV.
The CL-15's output impedance is 50 ohms (usable into passive controller).
Does this seem doable? The P'Luna's impedance is listed in kilo-ohms, while the CL-15's impedance is given in ohms. My newbie's provisional conclusion, then, is that there should be plenty enough of difference still.
However, one logical question--which component's impedance will be cut by half? Your language suggests it will be the P'Luna's, but my beginner's mind says it will be the CL-15's. If this is the case, then there may be too huge a difference created by the double hook-up, dropping the CL-15's output impedance by so much that the signal coming in from at least one of the outputs of the CL-15 will look to the P'Luna like a short. This happened with the ECI 3 amp already, although I realize I'm speaking hypothetically with regard to the P'Luna. I still haven't tried it.