Matt, be careful, RAID striping gets you transfer speed, not redundancy. Let me try RAID 5 again. Say you want to store 3 numbers -- 012, 147, and 532. With the four disks, RAID 5 puts 012 on Disk A in Block/Sector X. In that same Block/Sector on Disk B, it puts 147. In that same Block/Sector on Disk C, it puts 532. In that same Block/Sector on Disk D, it puts 691, which is the sum of what is on A, B and C in that location. So...
If Disk A goes bad, it can recover the data for Block/Sector X on that disk by taking 691 and subtracting what is on that Block/Sector on Disks B and C: 691-(147+532)= 012.
If Disk B goes bad, it can recover the data for Block/Sector X on that disk by taking 691 and subtracting what is on that Block/Sector on Disks A and C: 691-(012+532)= 147.
If Disk C goes bad, it can recover the data for Block/Sector X on that disk by taking 691 and subtracting what is on that Block/Sector on Disks A and B: 691-(012+147)= 532.
Disk D, obviously, can be recreated from A, B and C. This is a simplistic version, but RAID 5 is higher efficiency than mirroring because the effective storage you get is (N-1)*S, where N=number of identical disks and S=size of disks. For mirroring, obviously, the efficiency is N*S/2.
Maybe the tera isn't pretty, but mine's in my closet, do I don't worry about it. ;)
Good luck--as far as Mac Mini specs go, I bought a 1.4GHz one with the bigger memory package and it was overkill for doing audio.
If Disk A goes bad, it can recover the data for Block/Sector X on that disk by taking 691 and subtracting what is on that Block/Sector on Disks B and C: 691-(147+532)= 012.
If Disk B goes bad, it can recover the data for Block/Sector X on that disk by taking 691 and subtracting what is on that Block/Sector on Disks A and C: 691-(012+532)= 147.
If Disk C goes bad, it can recover the data for Block/Sector X on that disk by taking 691 and subtracting what is on that Block/Sector on Disks A and B: 691-(012+147)= 532.
Disk D, obviously, can be recreated from A, B and C. This is a simplistic version, but RAID 5 is higher efficiency than mirroring because the effective storage you get is (N-1)*S, where N=number of identical disks and S=size of disks. For mirroring, obviously, the efficiency is N*S/2.
Maybe the tera isn't pretty, but mine's in my closet, do I don't worry about it. ;)
Good luck--as far as Mac Mini specs go, I bought a 1.4GHz one with the bigger memory package and it was overkill for doing audio.