The correct internal-inductance of Windfeld cart.?

Dear Axel: I think there is a misunderstood on communication. A long thread with so much information can help to understanding " troubles " like this one you " feel ".

IMHO I can't think that Lew has its own " agenda " looking to achieve some target different of what the thread is.
I know Lew and I can say " free " that is a trusty person in a whole mean.

I had and still have ( now less ) several troubles with the people brcause of the way I'm ( I mean so direct and not " politic ". ) and because problems to understand and to communicate due my not so good English.

This kind of things happen everyday in a forum like this but I'm sure that almost all ( including Lew ) the people that post here are " good meaning " and honest with them.

Regards and enjoy the music.
Raul.

Jonathan, You are correct. I just did not want to go into great detail on Dave's qualifications.

Blow my mind!
1) good to know, we have only sincere value seekers going on in thread. I'm genuinely relieved.

2) I must be getting confused between the different participants? If that is so, my sincere apology.

3) Why didn’t Dave step up to the plate and tell me he is a SUT manufacturer, maybe he thinks we all know this? Well, as you can see – I didn’t.

4) To boil all this down, there is actually ONE, and only ONE simple disagreement here, that I can see.

- Can a cart be generating more current when it operates into a lower impedance.

- Dave (our SUT Man) vehemently defends, that by the “First principle of Thermodynamics” that is in NOT POSSIBLE, and that therefore the term “current mode” (not my own as I also stated before) is NONSENSE to put it simple.

- Everything else that’s been said and argued here, always came back to this difference in our understanding. He maintains a cart has a ‘fixed’ Voltage AND a fixed Current.

- So who’s got it wrong?

- Can we maybe agree that a GENERATOR, when demanded to operate into a lower impedance CAN deliver more current? If NOT, the voltage would drop and the light go out? If that is not the case then I am truly misinformed.

- Next, is the question what happens if we ‘down-load’ a cartridge (no SUT involved)? We lower the phono-pre’s input impedance from 47k to what ever our parallel resistor we picked will produce i.e. Rpre * Rload / (Rpre+Rload); just to make sure we are still on the same page, I know it’s what (most) everyone knows or at should know.

- Now we get back to the current issue. What will happen in that cart coil?! Will the current drop? Stay constant? Or rise? Remember we are talking about DAMPING the cart. So how does that damping work? How do we damp an e.g. woofer coil? By making MORE current available due to a higher ‘damping factor’ of an amp i.e. nothing else than simply having a MUCH lower output impedance for that amp, so it is less ‘resistive’ to the flow of current. Can we agree on that! If not, --- well let’s see.

- So damping happens, if MORE, and not LESS current runs through a coil – it kind of ‘clamps’ it – as is often said, so as not to perform to its own ‘inclinations’.

- Back to the cart. We ALSO have seen a impedance lower than 47k is used for damping a cart (some MC carts are fine with 47k since they provide their own version of damping) So we ‘clamp’ it down and thereby not let it have it’s own behaviour and go wild from 10 – 12kHz on until it has to finally roll-off.

- So now back to my point with Dave. Given the cart is down-loaded, can it produce more current-output or not? If it can not --- how then will it be damped?

Let’s just leave there and see where this takes us.

Greetings,
Axel

A very interesting thread (and thus my bookmark)...

:-) T_bone,
heck, there is someone that seems to enjoy this, hm - kicking cans...
Makes it all worth it now, doesn’t it?
Thank you for sharing,
Axel