Why do digital cables sound different?

Looks like you're right audioengr. I got into an argument with Monstrous Mike one time about Manchester Biphase encoding. He was trying to say there was no digital edge, only FM modulated sine waves. From what I can find, you are right -- the signal is still sent as square waves from what I can tell (but not with sharp edges -- the standard should likely work even if the signal were closer to a sine wave, but with more jitter).

As for who I am Drubin, just an audio enthusiast, who lurks on the audoasylum cable forum under "audioNeil".

Picking up on what Redkiwi said about coax vs. digital, I and a friend were able to A/B the new Audioquest Optilink 5 with Audioquest's digital RCA, the VSD-4. The result was truly surprising. The Optilink glass fiber Toslink was significantly better in every way; soundstage, bass, "openness," highs, "air," -- you name it, the glass toslink was better, even though the data is just the same 0's and 1's. I don't have a clue why it sounded better, technically, but this was not even close. We were startled, honestly, at the difference. Moreover, the toslink was significantly louder at the same volume level, requiring us to match volume for the two. So bottom line is, for whatever reason, digital cables sound different, no question whatsoever.

Sean wrote:

If one could resonate a cable that introduced a perfect non-reactive 75 ohm load at that frequency, you would end up with no standing waves.

There may be no standing waves to a pure sine wave at that frequency, but you would certainly experience reflections with digital edges. There are only a couple of ways to eliminate reflections with digital signals, including:
1) series terminate (75 ohm driver) into a 75 ohm Zo cable - reflection from the end is absorbed at the driver.
2) parallel terminate a low-impedance driver into a 75 ohm Zo cable using a 75 ohm resistor at the end - no reflection.
3) Series and parallel terminate - (75 ohm driver) into a 75 ohm Zo cable with a 75 ohm resistor at the end - this cuts the signal in half, but eliminates all reflections.

Forgive me for coming late into conversation...

From what ive seen there is a major flaw in the spec itself The #1 contributer of EMI is the rise time. The quicker it
is the more EMI emitted. A common misconception is the Freq
is the culprit not true. Its seems to me that the rise times
are faster than needed for application. If some one knows why they used the 3mhz with a 12-15ns rise time... Please let me know? It doesnt make sense to me. Although those numbers are prehistoric it is asking for excessive EMI with
faster rise times than needed. Typically you would see a rise time more like 30 maybe as high as 80 for that type
of frequency.

Its like saying take 15min to drive to the store (a 5 minute drive) and then RUN in side and try and make up for lost time when you get there.

As far as termination I agree with Audioeng. You have have
termination in place at reciever end. Its the reflection back thats the killer... Backwards crosstalk is evil sh*t in any system.

Audioengr: Tara worked with terminating impedances years ago. Silver center conductor, Teflon insulation, Silver braided shield, 75 ohm resistor from center to shield at the load end. It is a very nice sounding cable and not bright in the slightest bit.

As far as having to use a resistor(s) to terminate the load, you would not need to do that IF the actual output impedance of the transport is 75 ohms, the cable is 75 ohms and the input of the DAC is 75 ohms. The problem is that none of these are exactly the correct impedance, so you have VSWR at the feedpoint, VSWR within the cable and VSWR at the load. If one could find out the actual output impedance of the transport and the input impedance of the DAC, it would be easy to make up a section of cable that would act as an impedance transformer. This would minimize standing waves / reflections and maximize power transfer. THAT was the point that i was trying to explain. Obviously, you could not market this cable as the specific values would change component by component.

As far as terminating the cable with a resistor at the load end, that would NOT solve an impedance mismatch at the source end. An impedance bump ANYWHERE along the signal / data path will result in reflections back to the source. Sean
>