Regarding the oscilloscope waveforms shown at the link Eherdian provided, I'm not sure how they prove anything about anything.
It seems to me that the differences shown for the two orientations mainly involve interplay between the following factors:
1)The difference between the impedance between his fingers and one end of the resistor, and the impedance between his fingers and the other end of the resistor. Each of those impedances being comprised mainly of capacitive coupling between his fingers and the resistive element, plus some fraction of the total resistance of that element.
2)The impedance of the leakage path between the probe's ground and the scope's AC power input. Note that the time scale on the scope is 10 ms/division, from which it can be seen that the "signal" is comprised mainly of 50 Hz (he is evidently in a 50 Hz rather than 60 Hz country).
3)The input impedance of the scope/probe combination (i.e., the impedance that is seen "looking into" the tip of the probe, relative to its ground).
4)The relation between the value of the resistor and the input impedance of the scope/probe combination.
5)The impedance from his fingers through his body and through any path that may exist from there to AC/earth ground.
I see no reason to expect the net result of all of that to be equal for the two orientations, regardless of whether or not the resistor would have directional characteristics when inserted into a circuit. That conclusion would be true even if he managed to grasp the resistor exactly at its mid-point, due to the differences in AC leakage to the probe's ground and its tip.
BTW, although I haven't taken the time to read a lot of the posts in this thread, I happened to notice the one dated 10-22-12 from Larryi. As is almost invariably the case with his posts, it strikes me as being technically plausible, ringing true, and being an important point.
Regards,
-- Al
It seems to me that the differences shown for the two orientations mainly involve interplay between the following factors:
1)The difference between the impedance between his fingers and one end of the resistor, and the impedance between his fingers and the other end of the resistor. Each of those impedances being comprised mainly of capacitive coupling between his fingers and the resistive element, plus some fraction of the total resistance of that element.
2)The impedance of the leakage path between the probe's ground and the scope's AC power input. Note that the time scale on the scope is 10 ms/division, from which it can be seen that the "signal" is comprised mainly of 50 Hz (he is evidently in a 50 Hz rather than 60 Hz country).
3)The input impedance of the scope/probe combination (i.e., the impedance that is seen "looking into" the tip of the probe, relative to its ground).
4)The relation between the value of the resistor and the input impedance of the scope/probe combination.
5)The impedance from his fingers through his body and through any path that may exist from there to AC/earth ground.
I see no reason to expect the net result of all of that to be equal for the two orientations, regardless of whether or not the resistor would have directional characteristics when inserted into a circuit. That conclusion would be true even if he managed to grasp the resistor exactly at its mid-point, due to the differences in AC leakage to the probe's ground and its tip.
BTW, although I haven't taken the time to read a lot of the posts in this thread, I happened to notice the one dated 10-22-12 from Larryi. As is almost invariably the case with his posts, it strikes me as being technically plausible, ringing true, and being an important point.
Regards,
-- Al