Attainable???...Yes. Practical???...Here are the issues.
You didn't specify which projector you would use. Knowing the projector would indicate the lens ratio. A simple equation is to divide the throw distance by the lens ratio and you will get your screen width. Assuming a 20' throw (LENS to screen) and a lens ratio of 1.5 (just a general assumption), your screen width would be 13.3'. This gives you a screen height of 10', assuming a 3 x 4 aspect ratio. Since we don't know how bright the projector is and how much ambient light is in the room at any given time, there are more factors to explore. I realize I made quite a few assumptions, but if you fill in the missing info I can make some suggestions.
Rayd
You didn't specify which projector you would use. Knowing the projector would indicate the lens ratio. A simple equation is to divide the throw distance by the lens ratio and you will get your screen width. Assuming a 20' throw (LENS to screen) and a lens ratio of 1.5 (just a general assumption), your screen width would be 13.3'. This gives you a screen height of 10', assuming a 3 x 4 aspect ratio. Since we don't know how bright the projector is and how much ambient light is in the room at any given time, there are more factors to explore. I realize I made quite a few assumptions, but if you fill in the missing info I can make some suggestions.
Rayd