There is no link between the db and the ohm rating.
The dB rating basically tells you how loud the speaker will sound when driven with a certain amount of power.
The ohm rating, the impedance, can tell you how difficult it is for an amplifier to jamn a certain amount of power into the speaker. Neither a very low nor a very high impedance is desirable ... most amps are happiest around 8ohms ... they're designed that way.
Read on if you want to get technical (though it's 10 years since I did any amplifier design).
Amplifiers are limited by the current supply (usually down to size of transformers, capacitors, and duration of the loud passage), and by maximum output voltage, which is an inherent part of the design (usually near the power rail voltage, switched by the power transistors for SS amps).
From Ohm's law, V=I*R, and from the power law P = V * I one can derive that the power delivered to the speakers can be expressed in terms of voltage OR current :
power = V*V/R OR
power = I*I*R
Therefore, given the maximum voltage of the amplifier, or the maxiumum continuous current (or both), and given the worst case R, you could calculate the maximum power which could be driven into the speakers. (This is theoretical and the real value is a little lower).
So power delivery to the speakers when the speakers are higher impedance is usually limited by the maximum voltage of the amplifier (before clipping occurs).
Conversely when speakers have very low impedance the power delivery is limited by the current driving ability of the amplifier.
If you can find out the rail voltage and maximum continuous current of your amplifier and the minimum and maximum impedance of your speakers you could calculate a rough maximum power transfer, then use the dB efficiency to come up with the SPL. Of course, they're all AC signals, so you need to multiply by 1/root PI, or something like that .. it's too long ago for me to remember.
The dB rating basically tells you how loud the speaker will sound when driven with a certain amount of power.
The ohm rating, the impedance, can tell you how difficult it is for an amplifier to jamn a certain amount of power into the speaker. Neither a very low nor a very high impedance is desirable ... most amps are happiest around 8ohms ... they're designed that way.
Read on if you want to get technical (though it's 10 years since I did any amplifier design).
Amplifiers are limited by the current supply (usually down to size of transformers, capacitors, and duration of the loud passage), and by maximum output voltage, which is an inherent part of the design (usually near the power rail voltage, switched by the power transistors for SS amps).
From Ohm's law, V=I*R, and from the power law P = V * I one can derive that the power delivered to the speakers can be expressed in terms of voltage OR current :
power = V*V/R OR
power = I*I*R
Therefore, given the maximum voltage of the amplifier, or the maxiumum continuous current (or both), and given the worst case R, you could calculate the maximum power which could be driven into the speakers. (This is theoretical and the real value is a little lower).
So power delivery to the speakers when the speakers are higher impedance is usually limited by the maximum voltage of the amplifier (before clipping occurs).
Conversely when speakers have very low impedance the power delivery is limited by the current driving ability of the amplifier.
If you can find out the rail voltage and maximum continuous current of your amplifier and the minimum and maximum impedance of your speakers you could calculate a rough maximum power transfer, then use the dB efficiency to come up with the SPL. Of course, they're all AC signals, so you need to multiply by 1/root PI, or something like that .. it's too long ago for me to remember.