George, after submitting my post just above I did notice something in your calculations that prompted me to look at them further. A minor correction: The attenuation at half the 3db bandwidth frequency won't be 1.5 db.
"-1.5 db" (in three places) should actually be about "-0.97 db," corresponding to:
20log(1/(Square root(1 + (f/f3db)^2)))
f/f3db, the ratio of frequency to 3db bandwidth, being 0.5 in your three corresponding examples.
Regards,
-- Al
"-1.5 db" (in three places) should actually be about "-0.97 db," corresponding to:
20log(1/(Square root(1 + (f/f3db)^2)))
f/f3db, the ratio of frequency to 3db bandwidth, being 0.5 in your three corresponding examples.
Regards,
-- Al