Nguyen787,
A doubling (2x) in voltage is (almost exactly) 6dB. A 10x in voltage is exactly 20dB. So for example if you have a 20x factor in gain then you could say: 20x = 2x * 10x = 6dB + 20dB = 26dB
Note that dB values are always added together (since dB values are really exponents), while their corresponding multiplication factors are multiplied together.
When comparing power: a 2x in power is approximately 3dB, while 10x is exactly 10dB.
The precise formula for converting Voltage ratios to dB is: dB = 20 * log(V1/V2), where V1 and V2 are two different voltages, and the log function is base-10. Note that if you flip V2/V1, you get the same magnitude dB value but with a different sign. For power ratios, it's: dB = 10 * log(P1/P2), where P1 and P2 are two different powers in the same unit (e.g. Watts).
So in my example with the Apollos, you start out by comparing Voltages:
20 * log(4V/1V) = 12.0412 dB
Thus, the 4V amp will require a 12dB higher input signal to achieve its "full output" (the typical definition of amplifier sensitivity), versus the 1V amp. Next we have to compare the difference in "full output" between the amps:
10 * log(250Watts / 25 Watts) = 10.0 dB
So the amp that puts out 250W will be 10 dB above the 25W amp when both are at full output. Add the two together: 12 + 10 = 22dB difference in amp gain.
--
Mike
A doubling (2x) in voltage is (almost exactly) 6dB. A 10x in voltage is exactly 20dB. So for example if you have a 20x factor in gain then you could say: 20x = 2x * 10x = 6dB + 20dB = 26dB
Note that dB values are always added together (since dB values are really exponents), while their corresponding multiplication factors are multiplied together.
When comparing power: a 2x in power is approximately 3dB, while 10x is exactly 10dB.
The precise formula for converting Voltage ratios to dB is: dB = 20 * log(V1/V2), where V1 and V2 are two different voltages, and the log function is base-10. Note that if you flip V2/V1, you get the same magnitude dB value but with a different sign. For power ratios, it's: dB = 10 * log(P1/P2), where P1 and P2 are two different powers in the same unit (e.g. Watts).
So in my example with the Apollos, you start out by comparing Voltages:
20 * log(4V/1V) = 12.0412 dB
Thus, the 4V amp will require a 12dB higher input signal to achieve its "full output" (the typical definition of amplifier sensitivity), versus the 1V amp. Next we have to compare the difference in "full output" between the amps:
10 * log(250Watts / 25 Watts) = 10.0 dB
So the amp that puts out 250W will be 10 dB above the 25W amp when both are at full output. Add the two together: 12 + 10 = 22dB difference in amp gain.
--
Mike