Hi Bob,
In the case of a capacitor, the voltage between the two plates or conductors is proportional to the charge that has accumulated on them, the charges being equal but of opposite polarity on the two plates. Charge accumulates as a result of current flow between each plate and the circuit the capacitor is connected to. Therefore the charge and hence the voltage across the capacitor are proportional to the integral of current. Therefore (assuming an idealized capacitor model) an infinitely fast step increase in current will result in a gradual linear ramp-up of voltage.
In the case of an inductor, a change in current results in a change of magnetic flux, which results in a voltage being induced that opposes the change in current. See these writeups on Faraday's Law and Lenz's Law. Therefore, voltage is proportional to the rate of change (the derivative) of current; therefore current is proportional to the integral of voltage, and so a step increase in applied voltage will result in a gradual linear ramp-up of current.
Best regards,
-- Al
In the case of a capacitor, the voltage between the two plates or conductors is proportional to the charge that has accumulated on them, the charges being equal but of opposite polarity on the two plates. Charge accumulates as a result of current flow between each plate and the circuit the capacitor is connected to. Therefore the charge and hence the voltage across the capacitor are proportional to the integral of current. Therefore (assuming an idealized capacitor model) an infinitely fast step increase in current will result in a gradual linear ramp-up of voltage.
In the case of an inductor, a change in current results in a change of magnetic flux, which results in a voltage being induced that opposes the change in current. See these writeups on Faraday's Law and Lenz's Law. Therefore, voltage is proportional to the rate of change (the derivative) of current; therefore current is proportional to the integral of voltage, and so a step increase in applied voltage will result in a gradual linear ramp-up of current.
Best regards,
-- Al