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Parallel Capacitors-Theoretical Question

I want to replace the capacitors in my speaker's crossover networks. My Large Advent's came stock with 13uf NPE's which I would like to replace with PIO caps. Unfortunately, PIO caps are unavailable in that value. What's the best way to get to 13uf, (12uf + 1uf) or (6uf + 7uf)?
This is a purely theoretical question and I realize either method would probably sound the same, but I'm wondering if there is a reason why one method would be preferred over the other. Are there phase, impedance or other issues associated with either method. I realize of course that I could simply use 12uf or 15uf and probably never notice anything given that the original 13uf NPE had a 20% tolerance, but in theory, what's the best way and why?
heyraz
jburidan
803 posts
 
I believe it's better to go with 6uF + 7uF.
Some cap makers have 6.2uF & 6.8uF values, e.g., ClarityCap MR (630V).
marakanetz's avatar
marakanetz
5,473 posts
 
The other safe way is to measure the actual capacitance of the original one and than choose out of many to match exactly.
heyraz OP
177 posts
 
Please remember this is a theoretical question. The original 13uf value may have been chosen because of availability and price at the time. The nominal value is probably something else. What I want to do is replace the capacitor with a value as close to the original without creating another problem.
almarg's avatar
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almarg
9,670 posts
 
Given that the paralleled caps would presumably be similar in design, I'm not sure that using dissimilar values would make any difference compared to using values that are close to each other. But my instinct would be to use values that are as close as possible, because doing that keeps the higher of the two values as low as possible. Everything else being equal, a cap having higher capacitance can be expected to have higher stray inductance, which would be undesirable if the difference were significant in degree.
In case of parallel caps you'll simply have larger tolerance.
I respectfully disagree. For example, 6uf +/-10% in parallel with 7uf +/-10% = 13uf +/-10%.

Regards,
-- Al
zoya
120 posts
 
Theoretical answer to the theoretical qustion is 2 + 2 = 3 + 1 = 3.5 + 0.5 = 4.

But in physical situation 12 uf + 1 uf will give an added benefit of a small value capacitor added in parallel to the larger value capacitor because small value capacitors are better for filtering higher frequencies. The rolloff of the filter will be the same but you will also filter out high order harmonics that will pass through higher value capacitors.
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