Inpep, you still appear to misunderstand the the terms voltage, power and current, and more important, how they relate to each other. If you will spend some time with this site:
http://www.allaboutcircuits.com/vol_1/index.html
until these relationships are second nature, you will understand what I am trying to say.
Speakers (with voice coils, and primarily woofers) need power (watts) if it takes work to move them (power = voltage x current.) BUT, they need those watts (power) to come primarily from a larger reservoir of voltage since voltage drops as power is consumed. An ESL needs power too, but from a reservoir of current. As the frequency rises and the impedance drops, yes, they need power too, but they are going to draw current out of those watts to maintain the strength of the static charge on the membrane. They don't need volts for that!
All amplifiers supply BOTH increasing voltage AND current as the volume (input signal to the amp) is increased. The maximum output of the amp (in watts) is a product of its max. voltage times its max. current, and those two can be in ANY proportion. But with tube amps, current is usually in larger proportion to voltage than in ss amps where it's the reverse. I just don't know how to say it any more clearly.
.
http://www.allaboutcircuits.com/vol_1/index.html
until these relationships are second nature, you will understand what I am trying to say.
Speakers (with voice coils, and primarily woofers) need power (watts) if it takes work to move them (power = voltage x current.) BUT, they need those watts (power) to come primarily from a larger reservoir of voltage since voltage drops as power is consumed. An ESL needs power too, but from a reservoir of current. As the frequency rises and the impedance drops, yes, they need power too, but they are going to draw current out of those watts to maintain the strength of the static charge on the membrane. They don't need volts for that!
All amplifiers supply BOTH increasing voltage AND current as the volume (input signal to the amp) is increased. The maximum output of the amp (in watts) is a product of its max. voltage times its max. current, and those two can be in ANY proportion. But with tube amps, current is usually in larger proportion to voltage than in ss amps where it's the reverse. I just don't know how to say it any more clearly.
.