Where on earth do you get the idea that "an XLR cable" has a 110 ohm impedance? And even if it did, do you count that as part of the output Z or does it add to the input Z? That choice would drastically affect the calculation. Of course, the higher the ratio above 1:10, the better the numbers look, but it usually makes no audible difference so long as the gain structure is sufficient. What may matter is input capacitance, which when the impedance match gets much less favorable (much below the 10X "minimum", approaching 1:1) begins to cause a high frequency roll off in the audible range. At a ratio of 1:8, that should not be a problem, either.
Re the Denafrips DAC, about which I know very little, if its output Z is 5000 ohms and if it is driving in voltage mode, no amount of current is going to help if the input Z of the driven component is much below the 10X rule. No matter what, if the input Z of the driven component is 5000 ohms, equal to the output Z of the Denafrips (1:1), then you would lose 50% of signal voltage to ground. The calculation for voltage remains the same regardless of current, in voltage drive. In a DAC, even that poor impedance match may not be noticeable, absent an effect of C on frequency response, because DACs make so much signal voltage, they can usually drive an amplifier even without a linestage. All you need is an attenuator.