Bi-amp vs Bi-wire ohm question???

It is my understanding the resistance is native to the speakers and you can't change it (resistance) by wiring.

So, bi-amping or bi-wiring the 804S will get you 8 ohms.

If the speaker is rated at 8 ohm - that should mean that by Ohms law, that the high and low should have a resistance of about 16 ohm each. When you parallel them, like strapping the hi's and low's together to run with one set of wires - it becomes 8 ohm (2 - 16ohm resistors in parallel).

But to answer your question - when you biwire - both of these wires still come together as one at your speaker terminals on your amp - so even if you biwire --- still 8 ohm load....

But to answer your question - when you biwire - both of these wires still come together as one at your speaker terminals on your amp - so even if you biwire --- still 8 ohm load....

This is true but if you measure the speaker terminals with an ohm meter you won't get a reading like Bluesbassplayer suggests. You may get an 8 ohm reading from the woofer but the tweeter will measure quite differently. There's more going on in the crossover than a simple resistance reading will tell.
Maybe someone else can explain or provide a source for a good explanation.

If the speaker is rated at 8 ohm - that should mean that by Ohms law, that the high and low should have a resistance of about 16 ohm each. When you parallel them, like strapping the hi's and low's together to run with one set of wires - it becomes 8 ohm (2 - 16ohm resistors in parallel).

Not true, because there is a crossover network between the speaker terminals and the drivers.

Ideally, an 8 ohm speaker will be 8 ohms at any frequency. (Of course it won't be, and any speaker will deviate somewhat from its nominal rating as a function of frequency, but that is a separate issue).

Therefore if the jumper between the speaker's low frequency and high frequency inputs is removed, looking into the high frequency input (with a high frequency input signal) there will be nominally an 8 ohm impedance, and looking into the low frequency input (at low frequencies) there will also be nominally an 8 ohm impedance. Looking into the low frequency input at high frequencies (i.e., with a high frequency input signal), there will be a very high impedance (ideally infinite). Looking into the high frequency input at low frequencies, there will be a very high impedance (ideally infinite).

None of that is changed by biwiring or biamping. Longhornguy is correct.

Regards,
-- Al