Hi Mark,
Regarding the relationship between gain and wattage, as I mentioned there tends in general to be a loose correlation, but one that is so loose that it is typically of no usefulness.
As you’ve probably found, the gain of both integrated amplifiers and power amplifiers is very often not specified. If Stereophile has reviewed the product the measurements section of the review will usually indicate the measured gain. In other cases the gain can be calculated to a reasonable approximation from the specified maximum output power and the specified sensitivity (the input voltage that is required to drive the amp to the specified maximum output power), as follows:
Gain is the ratio of output voltage to input voltage, expressed in db.
The ratio of two voltages, V1 and V2, are converted to db based on the formula (20 x logarithm(V1/V2)).
The rated maximum output power into 8 ohms (or 4 ohms) can be converted into voltage based on the equation P = (Vsquared)/R, where P is power in watts, V is volts, and R is resistance in ohms.
So for example in the case of an amplifier rated at 200 watts into 8 ohms and having 2 volt sensitivity, if we represent the output voltage corresponding to the 200 watts into 8 ohms as "Vout" and the 2 volt sensitivity as "Vin," we have:
200 = ((Vout)squared)/8
From which it can be calculated that Vout = 40 volts
Therefore the gain in db is
20 x log(Vout/Vin) = 20 x log(40/2) = 26 db
That is an approximation, as I indicated, in part because it does not reflect margin that may be built into the maximum power specification. But it will generally be a reasonably good approximation for most purposes.
Also, note that for a tube amp having 4 and 8 ohm output taps the gain will be approximately 3 db less for the 4 ohm tap than for the 8 ohm tap.
If you have a scientific calculator these calculations are very easy to do. Alternatively, the calculator that is built into Windows can be set to scientific mode, although I find using it to be somewhat clumsy.
Best regards,
-- Al
Regarding the relationship between gain and wattage, as I mentioned there tends in general to be a loose correlation, but one that is so loose that it is typically of no usefulness.
As you’ve probably found, the gain of both integrated amplifiers and power amplifiers is very often not specified. If Stereophile has reviewed the product the measurements section of the review will usually indicate the measured gain. In other cases the gain can be calculated to a reasonable approximation from the specified maximum output power and the specified sensitivity (the input voltage that is required to drive the amp to the specified maximum output power), as follows:
Gain is the ratio of output voltage to input voltage, expressed in db.
The ratio of two voltages, V1 and V2, are converted to db based on the formula (20 x logarithm(V1/V2)).
The rated maximum output power into 8 ohms (or 4 ohms) can be converted into voltage based on the equation P = (Vsquared)/R, where P is power in watts, V is volts, and R is resistance in ohms.
So for example in the case of an amplifier rated at 200 watts into 8 ohms and having 2 volt sensitivity, if we represent the output voltage corresponding to the 200 watts into 8 ohms as "Vout" and the 2 volt sensitivity as "Vin," we have:
200 = ((Vout)squared)/8
From which it can be calculated that Vout = 40 volts
Therefore the gain in db is
20 x log(Vout/Vin) = 20 x log(40/2) = 26 db
That is an approximation, as I indicated, in part because it does not reflect margin that may be built into the maximum power specification. But it will generally be a reasonably good approximation for most purposes.
Also, note that for a tube amp having 4 and 8 ohm output taps the gain will be approximately 3 db less for the 4 ohm tap than for the 8 ohm tap.
If you have a scientific calculator these calculations are very easy to do. Alternatively, the calculator that is built into Windows can be set to scientific mode, although I find using it to be somewhat clumsy.
Best regards,
-- Al