This requires use of the pythagorian theorem: a2 + b2 = c2
a =height, b = width, c = diagonal measure
a = 22.5 , b = 40 (16:9, so 22.5 divided by 9 then multiplied by 16 = 40 inches.)
a2 = 506.25
b2 = 1600
c2 = 2106.25
c = 45.89 inches
However, the height of 36 inch 4:3 TV should calculate out this way:
3x = height, 4x = width, 36 inches = diagonal measure.
(3x)2 + (4x)2 = (36)2
9x2 + 16x2 = 1296
25x2 = 1296
x2 = 1296/25
x = 36/5
3x = 21.6 inches
Therefore an equivalent 16:9 TV should be:
a = 21.6, b = 38.4
a2 = 466.56
b2 = 1474.56
c2 = 1941.12
c = 44.06 inches
So, a 4:3 tv of 36" diagnal should actaully be the same height as a 44" 16:9 TV
a =height, b = width, c = diagonal measure
a = 22.5 , b = 40 (16:9, so 22.5 divided by 9 then multiplied by 16 = 40 inches.)
a2 = 506.25
b2 = 1600
c2 = 2106.25
c = 45.89 inches
However, the height of 36 inch 4:3 TV should calculate out this way:
3x = height, 4x = width, 36 inches = diagonal measure.
(3x)2 + (4x)2 = (36)2
9x2 + 16x2 = 1296
25x2 = 1296
x2 = 1296/25
x = 36/5
3x = 21.6 inches
Therefore an equivalent 16:9 TV should be:
a = 21.6, b = 38.4
a2 = 466.56
b2 = 1474.56
c2 = 1941.12
c = 44.06 inches
So, a 4:3 tv of 36" diagnal should actaully be the same height as a 44" 16:9 TV