In other words easy to drive speakers that are as close as possible to a
pure resistive load, which Ralph there are not many good ones, Magies
come to mind, not much else of worth, that why you push the Zero
Autoformer.
This statement is false. The most popular speaker with our M-60 was for many years the Merlin VSM which is a 6 ohm non-resistive load. I don't push the ZEROs because of the Maggies (our larger amps have no troubles with them; but many people seem to like the idea of a 60 watt tube amp on Maggies **that** is when I push the ZEROs for Maggies owners), I push them as problem solvers for tube and solid state amps. Its a much larger picture than you want to paint: if it were really that small as you suggest we'd not have been able to be in business for 41 years...
Gryphon top of the line amps will blow to hell all the tubes in all the
tube amps Ralph has ever touched. Along with all Classic Audio speakers
and Technics DJ turntables. Nothing does power and current like big
Gryphons.
The Gryphon amps are excellent! I was in the Gryphon room at CES years ago and witnessed a reviewer threatening the owner of Gryphon that if he didn't give the amp to him for free, it would be a bad review. The Gryphon owner had more ethics than that and it didn't go well; that reviewer pretty well shut down Gryphon sales in the US for over a decade. I admired them as they did amazing extrusions on their heatsinks, supported balanced operation properly and generally built an extremely high quality product.
Not sure how any amplifier blows a set of speakers and a turntable 'all to hell though'- that part of your statement seems nonsensical. Your statement about power **and** current does not make sense either and here's why: if an amp can make a given power into a given load (say 300 watts into 2 ohms) we can determine the current easily enough:
First, Ohm's Law relates voltage, current and resistance R=V/C
From that the power formula derives: 1 watt is equal to 1 volt times 1 amp.
If you state it in terms of resistance
The power formula is Power = (current squared) times resistance.
So plugging in the values: 300 = (current squared) times 2
solving for current squared we get 150, the square root of that is 12.25 amps.
From this I hope that you can see that it does not matter what kind of amp makes that power- the current will be the same; power (wattage) is the result of current and voltage together- current cannot exist without voltage.