@shadorne
The article that you provided indicates:
"Expressed as a formula, the intensity of a sound in decibels is 10 log10 (S1/S2), where S1 and S2 are the intensity of the two sounds; i.e., doubling the intensity of a sound means an increase of a little more than 3 dB."
The article I provided indicates (among other text, and significantly more comprehensive than the article you provided):
"you'll see that doubling the sound pressure gives an increase of four in the intensity, so an increase in the sound level of 6 dB, whereas doubling the power increases the intensity by a factor of two, so an increase of 3 dB."
So given your latest post there appears to be no disagreement, or any offense to Rod Serling.
But this is very different than your statement that I disagreed with. You stated, "3 dB is twice the volume mathematically". Can you provide a link to support that (volume, not power)?
I can assure you, physical laws and the work of greats such as Alexander Graham Bell are not in question here.
The article that you provided indicates:
"Expressed as a formula, the intensity of a sound in decibels is 10 log10 (S1/S2), where S1 and S2 are the intensity of the two sounds; i.e., doubling the intensity of a sound means an increase of a little more than 3 dB."
The article I provided indicates (among other text, and significantly more comprehensive than the article you provided):
"you'll see that doubling the sound pressure gives an increase of four in the intensity, so an increase in the sound level of 6 dB, whereas doubling the power increases the intensity by a factor of two, so an increase of 3 dB."
So given your latest post there appears to be no disagreement, or any offense to Rod Serling.
But this is very different than your statement that I disagreed with. You stated, "3 dB is twice the volume mathematically". Can you provide a link to support that (volume, not power)?
I can assure you, physical laws and the work of greats such as Alexander Graham Bell are not in question here.