I've created a thread at DIYaudio.com.
https://www.diyaudio.com/forums/multi-way/345669-exercise-converting-speaker-time-phase-coherent.htm...
https://www.diyaudio.com/forums/multi-way/345669-exercise-converting-speaker-time-phase-coherent.htm...
First order/Time Phase-Coherent speakers discussions
"The game is done! I’ve won! I’ve won!"
I've created a thread at DIYaudio.com. https://www.diyaudio.com/forums/multi-way/345669-exercise-converting-speaker-time-phase-coherent.htm... |
Hello! Audiophile friend urged me to jump into this discussion with some of my ideas. Here goes my take on phase-coherent speakers and first-order crossovers: A perfect transition from an electrical signal to acoustic sound is defined by the simple so-called all-pass transfer function defined by: -St (1) f(s) = Ke (note: this dumb website does not allow math symbols, sorry) For perfect fidelity in acoustic space this equation defines it, where S is the complex frequency variable S = p+jw and K,T are real positive constants and =2.718...... One can realize a loudspeaker crossover in Laplace-Transform form by expanding (1) in an infinite series and taking only the first term in (2) to yield (3), as: 2 (2) F(s) = e = 1/(1 + St + (St) + etc.......) Taking just the first term yields (3) f1(S) = 1/ (1 + St) Laplace transform of (2) represents circuit consisting of a coil of T Henries in series with a 1-ohmresistor. (You need to imagine circuit because website cannot draw schematic symbols!) Replacing variable S with its inverse 1/S in (3) yields St/(1 + St) or, a single capacitor and resistor in series: (4) f2(S) = St/(1 + St) Equation (3) is transform of a woofer crossover in circuit, equation (4) is transform of a tweeter in a crossover circuit. Now add (3) and (4) to obtain: (5) f1(S) + f2(S) = 1/(1 + St) + St/(1 + St) = 1. Sum adds to a constant, the number one! The crossover is perfect, a constant. No variables are present. Speaker will be flat in amplitude and linear in phase!!!! Crossover uses one coil and one capacitor!!!! Simple!!!! Here I show why people are in love with first-order crossovers. Realized carefully, a first-order crossover system will work reasonably well and satisfy almost anyone with decent sound. RIMO |