Chained speakers signal connected in series

 I will share the numbers once I'm done! Your analogy of a 103dB speaker also got a chuckle out of me. 103dB @ 1watt,1meter distance is not that loud, really.

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At 1000 watts with 12 ribbons and planars drivers, I'm no where NEAR my system. Not to mention the other 20 MB and sub drivers, driven by 2 12K class ds. It would cave your chest in.. MB are 93% E 8" drivers

Add my center channel of 16 more neo 8 planars. We are close to BLASTING the meat off the bone at 3 meters. I would say 130 db would be conservative. I have guinea pigged a few smart A$$ kids.. It's left them with a nose bleed or two.. LOL

I'm sensitive I guess. :-)

I actually have ear plugs in right now!! Unless I'm sleeping or listening to music/TV they are in my ears.. At 66 I still spend a lot of time with noisy hand held tools.. My clunky fingers have a tough time after I use them for a while.. THUS the ear plugs stay in.. Not out.. 45 year now. 

I listen most of the time after 23-2400 hours. 2-6 watts with 6V6s and maybe 20 watts for the bass and 10-15 watts sub.. I can hear it EASY in a 25 x 40 x 16 wood shop.

BUT the issue is in series, imhififan made a good point. IN SERIES the second speaker is getting only what is NOT filtered from the first XO.

Sound different? Sound BAD is more like it, real bad.

Parallel will work with a stout class D no problem. I'd even say work well.

I like mids 300 hz and UP AT least 6 ohms 10-16 is even better. Valves don't like that low of numbers. My Macs will run at 2 ohms.
Sound BAD at best.. 8 ohms or > they just twinkle.

Regards

I just read your post "DOES NOT change." fiesta75.

Sure it does IN series. The signal path has gone through EVERY component in the first speaker box IF it is a typical series XO. IF it is a parallel OX design (like a Quasi second order) and BI AMPABLE it would STILL pass through all the XO filters BACKWARDS (?) in the bass or the mid/highs XOs after it went through every component in the first speaker box..  + - + -, is every component including the speaker terminals and VCs.

It’s IN SERIES, not Series/parallel or Parallel/series BUT one AFTER the OTHER.

How you like that for Techno talk.. I use to have to teach smart apprentices. Oh yea, they were smart alright. .Just like I use to be.. :-)

How’s my math by the way, you notice, no numbers applied for the unsighted.. I’m close after 50+ years of welding.. I strike an arc I can see just fine. TIG, MIG, TWIG, TWIT, TWILL, TWASEN’T.. LOL

Regards

I will post some sketches tomorrow. If you connect the second speaker just across the woofer of the first speaker, the second speaker will see both inductors. I'll show you what I mean, but if you care to just plug some numbers into the "grade school" math equations, you will be able to see without me having to post anything... Elementary school?🤣

@fiesta75, 

Can we agree that Rt equals 16ohms in series?

Yes

Can we agree that Lt = L1 + L2 in series?

No, IMO, the first woofer will see the voice coil of second woofer as an inductor in series, same for the second woofer, it will see the voice coil of first woofer as an inductor.
I think the total inductance should be Lt = L1 + L2 + Lvc1 + Lvc2

Can we agree that 1/Ct = 1/C1 + 1/C2 in series?

Yes

it's yes to the above, then simply plug those numbers into the equations. f = R/2πLQ and f = Q/2πRC. 

May be a crossover design simulator software can give us a better answer.

Even if L1 and Lvc1 are present, L2 and Lvc2 are also present. If the frequency of the crossover is say 2kHz., it will remain at 2kHz., because L1+Lvc1 equals L2+Lvc2. Is that not correct? L1 = L2 and Lvc1 = Lvc2 for each speaker. Both inductances are present whether they are used to calculate the crossover frequency or not. Correct?
Perhaps a crossover design simulator would give us a better answer, I am willing to listen to your presentation. That could save me the hassle of posting sketches. I think we are both capable since we have been working to solve the problem with likklegerry's crossovers. I will be waiting.