I will post some sketches tomorrow. If you connect the second speaker just across the woofer of the first speaker, the second speaker will see both inductors. I'll show you what I mean, but if you care to just plug some numbers into the "grade school" math equations, you will be able to see without me having to post anything... Elementary school?🤣
Chained speakers signal connected in series
I have two pairs of the same model speakers (Tannoy SGM 10B) connected in series to two monoblock amplifiers. The left channel amp drives two speaker cabinets on a left (speakers L1 and L2) and the right channel amp drives two speaker cabinets on a right (speakers R1 and R2).
The positive speaker output of the left amp is connected to a positive post of the first speaker L1(+). Then the negative post of the same first speaker L1(-) is connected to positive post of the second speaker L2(+) with the its negative post L2(-) connected to the amplifier's negative speaker output.
AMP(+) > L1(+)
L1(-) > L2(+)
L2(-) > AMP(-)
Both left channel speakers have a cross-overs build in. Does the audio signal that the first speaker L1 receives from amplifier is any different from a signal the second speaker L2 receives from speaker L1? Does the crossover of the first speaker L1 modify the output signal that goes to a second speaker L2?
The positive speaker output of the left amp is connected to a positive post of the first speaker L1(+). Then the negative post of the same first speaker L1(-) is connected to positive post of the second speaker L2(+) with the its negative post L2(-) connected to the amplifier's negative speaker output.
AMP(+) > L1(+)
L1(-) > L2(+)
L2(-) > AMP(-)
Both left channel speakers have a cross-overs build in. Does the audio signal that the first speaker L1 receives from amplifier is any different from a signal the second speaker L2 receives from speaker L1? Does the crossover of the first speaker L1 modify the output signal that goes to a second speaker L2?
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- 27 posts total
@fiesta75, Can we agree that Rt equals 16ohms in series?Yes Can we agree that Lt = L1 + L2 in series?No, IMO, the first woofer will see the voice coil of second woofer as an inductor in series, same for the second woofer, it will see the voice coil of first woofer as an inductor. I think the total inductance should be Lt = L1 + L2 + Lvc1 + Lvc2 Can we agree that 1/Ct = 1/C1 + 1/C2 in series?Yes it's yes to the above, then simply plug those numbers into the equations. f = R/2πLQ and f = Q/2πRC.May be a crossover design simulator software can give us a better answer. |
Even if L1 and Lvc1 are present, L2 and Lvc2 are also present. If the frequency of the crossover is say 2kHz., it will remain at 2kHz., because L1+Lvc1 equals L2+Lvc2. Is that not correct? L1 = L2 and Lvc1 = Lvc2 for each speaker. Both inductances are present whether they are used to calculate the crossover frequency or not. Correct? Perhaps a crossover design simulator would give us a better answer, I am willing to listen to your presentation. That could save me the hassle of posting sketches. I think we are both capable since we have been working to solve the problem with likklegerry's crossovers. I will be waiting. |
While you're listening through your pencils: you're going to simply ignore everything that a voice will induce to a signal, when actually presented with music? HILARIOUS (in a tragicomedic way)! Best broaden your horizons, as to what goes on (and can be measured/calculated) when certain elements (ie: caps and voice coils) are actually under the influence of *changing frequencies (ie: an actual audio signal) as opposed to DC (ie: a multimeter). *Ever looked at the impedance plot of a woofer, actually being used in a circuit? (https://audiojudgement.com/speaker-impedance-curve-explained/) (https://www.apogeeweb.net/tools/reactance-calculator.html) Perhaps: even plug some of those facts, into your calculations? (http://oer2go.org/mods/en-boundless/www.boundless.com/definition/reactance/index.html) NAH, why bother with Physics, right? 🙄 ps: I only bother posting such things, knowing they will be ignored by most, BUT: hoping someone out there remains interested in facts/learning. Happy LISTENING! |
@fiesta75, I think it was 7 or 8 years ago, my friend use Hornresp (http://www.hornresp.net/) did a simulation on his speakers and found that connect two speakers in series the low pass filter cutoff frequency get lowered, our conclusion was the first woofer will see the voice coil of second woofer as an inductor in series, same for the second woofer, it will see the voice coil of first woofer as an inductor in series, and caused crossover point lower than a single woofer alone. |
- 27 posts total