Thank you for sticking with me on this, @erik_squires , if you could bear with me just a bit longer:
if this was the ideal circuit in a utopian world of circuitry and there was NO resistance
(V=5A x 0R=0V)
then you are saying that although 5 amps of current are flowing through this white neutral wire, it is not dangerous because the formula dictates that 0 volts are created. In this hypothetical circuit. Correct?
But you are also saying that in reality this hypothetical circuit doesn't exist, and the example you used of what does exist is
v=5Ax10R=50V
so the white wire (with 10R) is not only carrying current, but because of the 10R it is also carrying volts? Is that correct?
(And on an aside, doesn't this mean that the old saying, "it's not the volts but the amps that kills you" is not exactly correct, as I am getting out of this that amps without R would not be dangerous?)
But back to my question that prompted this explanation from you: in the real world circuit that you used for an example
V=5Ax10R=50V
what happens to that formula when it reaches the neutral bar via the white wire? Is it that because of the massive ground cable that ALL resistance disappears at this point and the ingredients for the 50V are gone?