The correct internal-inductance of Windfeld cart.?


What (on earth) is the correct internal-inductance of the Ortofon Peer Windfeld cartridge?

They made a mistake in the brochure about the loading impedance: it says >10k but should read >10 ohms. This was admitted by the factory's techies.

The brochure also says internal-inductance: 700 mH !!!
This you would expect from an MM cart. Was this also a factor 1 000 error? I can not find ANY help on the web to clear this up. Can any one help?
axelwahl
:-) T_bone,
heck, there is someone that seems to enjoy this, hm - kicking cans...
Makes it all worth it now, doesn’t it?
Thank you for sharing,
Axel
3) Why didn’t Dave step up to the plate and tell me he is a SUT manufacturer, maybe he thinks we all know this? Well, as you can see – I didn’t.

I didn't know it was expected. Many forums frown upon manufacturers hawking their wares so I simply used my company name as my moniker. If anyone here thinks me not disclosing my industry nature was inappropriate, I apologize since the last thing I want to appear as is a "sock puppet". The idea that I wind transformers has nothing to do with my perceived technical inaccuracies in your posts which is the only thing I have responded to. If you want to go back point by point to clear up any possible misunderstandings I may have had, I'll gladly have that discussion. I specifically asked you to properly quote me since many of your comments attributed to me are improper interpretations of my intent.

enough of that, now onto the meat of your post.

- Can a cart be generating more current when it operates into a lower impedance.

Absolutely, it is a simple oms law thing from the first order perspective. This isn't even worth discussion and hasn't ever been something I have disagreed with.

- Dave (our SUT Man) vehemently defends, that by the “First principle of Thermodynamics” that is in NOT POSSIBLE, and that therefore the term “current mode” (not my own as I also stated before) is NONSENSE to put it simple.

I simply used the first law of thermodynamics to state that a SUT cannot increase both voltage and current at the same time since that would increase power. Of course an increase of voltage into a fixed load will increase current but I did not interpret your writings as saying such. If I misunderstood your intent the proper response would have been to discuss the topic on point with proper quoting so we could clear up the misunderstanding.

He maintains a cart has a ‘fixed’ Voltage AND a fixed Current.

I have not suggested this. With both fixed voltage and current, there could be no AC (music).

The only thing I have taken issue with is your insistence that a SUT is required to make a Cartridge operate in "current mode". If you carefully read back through every post I have made in this topic, I hope that will be clear. If it isn't clear, tell me and I'll try to be more lucid in the future.

dave
Hi Dave,
this is getting us somewhere, I think.
I have no issue with what you say, so let's put this down to a number of 'crossed wires' on my side -- let peace be with us, it that is fine by you.

I stated somewhere, that you get 20 times the output voltage for FREE! (in that given example 30 dB SUT), and I think it was you, and some other contributor that took issue with this.

Well, you do get it for FREE. Since there is NO additional power input required such as in a gain-stage, to get just that. Never mind ohms law right now... You do get the additional ~ 30 dB gain for free! And that without added tube or SS derived noise. Seems I am selling your own stuff to you, it’s my pleasure (-:
Now please tell me where this statement is factually incorrect, Dave.

Jolly good, now how about the cart damping by increased current through the cart coil?
Tell me it this is correct? If not, how is the cart being damped then?!

Next, let us hear what is the difference in current when the cart goes into 47k impedance, and when it goes into an SUT with per example 10 ohm impedance?
More current? Well lots more, unless we want to argue about THAT some more.
If we do agree that it is more --- does it make sense to use the term "current mode"?

Since we are still with ohms law. If a cart works into a 47k impedance and then into a 10ohm impedance, in which situation do we expect the higher Voltage?
Will it be the same? Not according to the "First Law of Thermodynamics" as you quoted, since more current = less voltage, so the let's agree we have the higher Voltage at 47K impedance (i.e. into a phono-pre straight, no SUT) does the cart operate at a higher Voltage?
You said so, thereby what we have, "Voltage mode".

Maybe, just maybe, we can get it together...

Thank you for still being with us.
Greetings,
Axel
Post removed 
Axel,

I originally misinterpreted what you were saying about "free" voltage multiplication.

What is interesting about your experience with primary loading of the PW cartridge is that your ideal loading (the reflected load seen by the cartridge) is radically different when using that SUT than the recommended loading when using only an active phonostage or secondary loading.

I was wondering if you have any speculation as to why this is so. I know that some experts maintain that there is a specific "critical" load that effectively dampens the high frequency peak without excessively rolling off the high frequencies. I was wondering why it is not the same load (as presented to the cartridge) regardless of the type of downstream amplifying device.

I am asking this because my phonostage (Viva Fono) utilizes a SUT as the first stage voltage gain device (feeding a tube active stage). I don't even know the gain of the device, but, it is loaded at the primary with a 460 ohm resistor. This resistor is soldered across the back of the RCA input jacks. Because of the difficulty in accessing and changing the resistor value (tight space, a lot of nearby wires), I've limited my experiments to connecting and disconnecting one leg of the resistor. I am now wondering if I should try a MUCH lower value resistor.