Why is the price of new tonearms so high


Im wondering why the price of new tonearms are so high, around $12k to $15k when older very good arms can be bought at half or less?
perrew

Completely wrong.

Your first paragraph makes no sense: the effective mass of an arm is simply the moment of inertia divided by the square of the effective length.

In the second para you present a supposition which I have already shown to be wrong but you do not support it with evidence.


Mark Kelly
Mark,
Are you implying that in all situations where the effective mass or "inertial mass" (not sure which one you mean, or if you mean to say they are the same) is 25g, and the effective length is identical (let's just say that the combination of total mass at the effective length is identical and the effective length is identical), that the maximal variation due to warp riding (which you put at 6.2nM) will be identical, regardless of compliance of cart, and regardless of what force mechanism is keeping the stylus on the record?

T-Bone

Yes, that is what I am saying.

It follows from a simple torque balance on the arm according to D'Alembert's principle. Rather than boring everyone by converting forces to torques and computing moments of inertia, I used the concept of equivalent mass.

BTW the figure given only applies to the example given, obviously different constraints will result in different figures.

Note that this is a force variation, the way the cart responds to the force variation will depend on the compliance. Also note the assumption of equal inertia is not equivalent to an assumption of equal structure but the differences are so small as to be immaterial to the argument.

Mark Kelly
Assume a standard "taco warp" so the warp frequency is 7 rad.s^-1.
Hi Mark - please, what's a "taco warp"? I'm assuming it's not related to female tonearm connectors :) . . . but seriously, while I can't really conceive of a standard shape to the minor warps on my records (for those that actually get played, not the obviously 'defective' sort) . . . just going by the tempo of the excursions, I'm guessing that 1-3 Hz is about the frequency range of most of them. So your 7 rad/sec (a little over 1 Hz) is a good figure, but probably a little far away from resonance for calculating good maximum/minimum changes in VTF.
If the inertial mass were 25 g (say 15g arm plus 10g cartridge) and the warp were 5mm high, the maximal variation would be around 6.2 mN. A similar calculation allows a maximal warp tolerance to be derived for any arm / cart combination as a function of VTF.
But the record doesn't act directly on the effective mass of the arm/cartridge - the compliance of the cartridge is in series. So for the actual change in VTF, you'd need to add a scaling factor based on the cartridge/arm resonance, no? Also, the point of maximum/minimum force in the warp cycle will change with warp frequency, as will the phase relationship between the force exerted by the record on the stylus and the force exerted by the cartridge on the tonearm will change as the warp frequency approaches the primary resonant frequency.

Which makes me think that in most cases, the minimum/maximum cases of effective stylus VTF are unlikely to occur very near the tops/bottoms of the warp excursion, meaning that we're also going to see these extremes as occuring at a slightly altered VTA, the extent of which depends on the slope of the warp, hence its amplitude and frequency. Now my head's starting to spin . . .
The important point is that it has nothing to do with the balance of the arm but is stictly related to the moment of inertia (and the mass of the cart).
Yes, this is indeed the important point . . . but I would clarify that it's the moment of inertia from the effective mass of the arm/cartridge combination, coupled with the resonant behavior of the cartridge compliance interacting with this effective mass.

But the big point with static vs. dynamic-balance is . . . what exactly is issue that the dynamic-balance system is trying to solve? Is it always used as an attempt to improve the constancy of VTA with tonearm position? In the tonearms I've set up, it seems that many are position-sensitive (remove the mat from under the force gauge and get a different reading, etc.), and many are not . . . and this doesn't necessarily correlate with whether or not the particular tonearm has a dynamic-balance system. So it seems to me that it's more in the overall execution than anything else.
Just a short note from the office between two meetings....

I don't think I was completely wrong.
The inertia in a tonearm/cartridge combination does depend on the effective length, as this is not a homogenous corpus, but the majority of the mass is situated at the very end of the moving corpus - thus the inertia in a say 15 grams effective mass 12" tonearm with a given cartridge is always larger then in a 15 grams 9" tonearm with the very same cartridge.
Inertia is increasing with the distance to the center of movement.
The more so, the further away the majority of the mass from the dead center of movement.
Now we get closer to the model of a tonearm w/cartridge mounted far away from the pivot.
With the model of a pivot tonearm we are looking at the simplified calculation (taking the tonearm as a mass homogenous corpus) of (following Steiner AND WITHOUT including the cartridge mass at the moving tip of the lever !): J = 1/3 m x (2R) sq

J = inertia
m = mass
R = radius
sq = square

More to follow tonight.