Can a broken leg from a tube be soldered and used?

Newbee makes a good point. But you do have to feel confident you have a firm contact that won't short out during use. Also, as I recall the ceramic sockets for the 6C33C are fairly thick before you reach the metal contact points, which places a constraint on how short the pins can be and still achieve reliable contact.

There is no leg left on the damaged tube to make any contact to the socket.
Someone told me that the broken legs may not need any connnection to the circuit. So I just go ahead and plug the power.
Only one tube biased (a green line comes for each tube once biased). One tube did not glow at all. The other two tubes glowed, but did not bias.
Looks like three tubes are bad. The seller claimed that the amp worked just fine before shipping. What a life on used power amp!

In another thread (under misc forum) I mentioned that one int tube amp, which worked find before I sold it, was returned back to me with blown resistor. The seller demands a full refund minus shipping, claiming that I sold him a defective amp.

I feel like I am cursed by a tube daemon.

Dangerous to just take a chance that the missing leg is irrelevant. In fact, as far as I know, there is NO irrelevant pin on a 6C33C. Anyone who told you that is "blowing smoke". Here is the pin diagram URL. I believe pin 4 is the single large diameter one, so you can use that for reference:

http://www.audiomatica.com/tubes/6c33c.htm

By the way, pin 4 is the single "plate" connection. Pin 5 connects to both grids, and pin 3 connects to both cathodes. Despite the presence of dual grids and cathodes, this is not a dual section tube, because it has only one plate. The other pins in pairs subserve the filament connections. If you light only one filament (by omitting a single filament connection), then the tube is reduced in its ability to handle current, at the very least. Also, these tubes are not internally fused, so if they are overloaded they will arc.