Graham Phantom Supreme?

Here is a picture from

Graham 12'' Phantom IIs

The red signs are coming from the timeline Strobe (speed controller)

Dear Hiho, you're right.
I forgot - the Phantom is a semi-unipivot design.

Too bad Graham didn't put a detent on the center of the pivot cap so that I could use my feikert. Anyone have an idea how to measure for the exact center point so that I could make my own detent ? I am going to inquire with Graham directly about this.

With experience limited to seeing pictures of the Phantom2S, I'll ask, is it possible to acquire its center point with the cap off? Or other suggestions on how to accomplish use of the Feickert for this measurement? tia
 

From Bob Graham, via Musical surroundsings:

I checked with Bob Graham and while you are correct that the alignment jig is for the 9" arm, there is actually only a 1/2" difference in the effective length of the 9" vs the 10". Mr. Graham recommends moving the cartridge back in the headshell about .05" from what the gauge shows to achieve the proper overhang.

Effective Length: 10" = 248mm
Spindle to pivot distance: 10" = 229.4mm

Looks like an arc protractor is in order. There is still a wee bit of play with the headshell in the jig. Enough, imo that even with a 9" arm, you could be off slightly zenith angle wise.YMMV

I have a question _

I thought the way the magneglide system worked was that it was magnetically coupled to the arm, such that as the arm moved it followed. In Fremers review he stated there was no mechanical contact between the magneglide system and the bearing. Is this correct ?

Jtimothya - with regard to the feikert query, the true centre should be measured at the pivot point, not the centre of the cap. They will only be the same when the arm is dead level. Bearing in mind that the pivot is a radius tip in a sapphire cup the actual pivot point will be slightly forward of centre in the cup going towards the cartridge. Graham should be able to give you some guidance on this.