help with din to rca cable for creek amp?


I recently purchased a Creek audio systems cas 4040 amp. My source is amc cd8b cd player. The cd player has rca outs, the amp (which doesn't have a cd player input) has an aux input, which is 5-pin din. I can't find a cable to connect the two that works! I bought one (brand: Neutrik) cable that the seller said was for b&o equipment, and thinking that as the creek is european design, it might work...but no luck. Any suggestions would be greatly appreciated! Ben
128x128balthus
Thanks to all of you for your quick response and kind assistance. I purchased a Naim cable on the 'bay that the seller said would work, and if not he would refund. So I'm giving those a shot, and if they don't work out, I may look into having someone make me one custom. I am also sending an email to Creek to see if they have a cable they could supply, very interested to see what kind of a response I get! I'll post results of my efforts, and thanks again for sharing your expertise. Ben
I have a British Armstrong reciever that uses DIN connectors, and the ones for B&O and others work fine. I found some on Ebay for $5 for a full Tape Loop(ins and outs). While I was waiting, I went to radio shack and bought a 5 pin DIN plug, and some RCA plugs, and made my own. You can look up the pin configuration. The pins are usually numbered, but if you look at the plug from the back(where you would solder the wires on) the numbering goes from left to right 1 4 2 5 3. The gap is on the bottom.
1 is Left Channel output
4 is Right Channel output
2 is Common
5 is Right Channel input
3 is Left Channel input
I used this for making a phono connector and it worked perfectly. The pins are close together, and it is hard to solder them, but it can be done.
Do you have the manual for the Creek? Usually those manuals have the configuration of the pins (what is wire to what pin). If not, ask Creek if they have the layout of the 5 pins of the Din plug, so you can have cables made correctly if you need to. The pin configuration on the above post is probably correct.