Greg, you are confused, do some research and you will see you are wrong on all counts except that 6dB is 4x power.
Elvick's chart clearly shows a doubling of power for every 3dB. Robert Harley's book on high end audio states each increase in SPL of 3 dB requires a doubling of amplifier power output.
Yes, 6dB is 4 times the power but that is because it is 3dB plus 3dB which is double times double (2x2=4) however another 3db for a total of 9dB would be 8 times the power (2x2x2=8)
Your formula is for voltage, not power.
dB power is 10 log p1/p2
dB voltage is 20 log v1/v2
Why is one 10 and the other 20? Since power is proportional to the square of the voltage this keeps the dBs in step. An increase in voltage of 6dB will result in a 6dB increase of power. A few examples:
If I double the voltage I get 4 times the power (2 squared = 4)
Voltage dB = 20 log 2 = 6 dB
Power dB = 10 log 4 = 6 dB
If I produce 5 times the voltage I get 25 times the power (5 squared = 25)
Voltage dB = 20 log 5 = 14 dB
Power dB = 10 log 25 = 14 dB
and it isn't delta. Delta means the "amount of change" so the delta from 200 to 300W is 100W. The formulas use the ratio so you would take the log of 300 divided by 200.
tsk,tsk:)
cheers
Elvick's chart clearly shows a doubling of power for every 3dB. Robert Harley's book on high end audio states each increase in SPL of 3 dB requires a doubling of amplifier power output.
Yes, 6dB is 4 times the power but that is because it is 3dB plus 3dB which is double times double (2x2=4) however another 3db for a total of 9dB would be 8 times the power (2x2x2=8)
Your formula is for voltage, not power.
dB power is 10 log p1/p2
dB voltage is 20 log v1/v2
Why is one 10 and the other 20? Since power is proportional to the square of the voltage this keeps the dBs in step. An increase in voltage of 6dB will result in a 6dB increase of power. A few examples:
If I double the voltage I get 4 times the power (2 squared = 4)
Voltage dB = 20 log 2 = 6 dB
Power dB = 10 log 4 = 6 dB
If I produce 5 times the voltage I get 25 times the power (5 squared = 25)
Voltage dB = 20 log 5 = 14 dB
Power dB = 10 log 25 = 14 dB
and it isn't delta. Delta means the "amount of change" so the delta from 200 to 300W is 100W. The formulas use the ratio so you would take the log of 300 divided by 200.
tsk,tsk:)
cheers