The 100 db calculation was for the pair of speakers, and reflected the 3 db increase. On the other hand, I should mention that it assumed a 6 db reduction in SPL per doubling of distance, which might be a bit pessimistic (i.e., too large a number), considering the multiplicity of drivers the speakers have, that are spread out over a considerable height.
Assuming the 6 db reduction per doubling of distance is valid, though, which corresponds to 20 times the logarithm of the ratio of two distances, for the 9 foot distance you indicated the calculation works out to about 101 db, for the two speakers.
Also, if and when you perform the oscilloscope measurement, keep in mind that the word "peak" has to be applied with care. Amplifier power and voltage levels are specified on an rms (root mean square) basis, and on the assumption that the waveform is a sine wave. For a sinusoidal waveform, the number of rms watts is calculated based on a voltage equal to 0.707 times the maximum ("peak") voltage that is reached by the waveform. So the word "peak" in that context means something different than the "maximum" power level corresponding to a musical "peak," which refers to rms power and not instantaneous peak power.
In other words, what would be most meaningful is to determine the maximum voltage level that is reached under worst case listening conditions, multiply that number by 0.707, and apply the E^2/R formula to the result. Applying the E^2/R formula to the maximum voltage level that is reached would work in the direction of making the amplifier seem more underpowered than it may actually be, by a factor of about 2.
Regards,
-- Al
Assuming the 6 db reduction per doubling of distance is valid, though, which corresponds to 20 times the logarithm of the ratio of two distances, for the 9 foot distance you indicated the calculation works out to about 101 db, for the two speakers.
Also, if and when you perform the oscilloscope measurement, keep in mind that the word "peak" has to be applied with care. Amplifier power and voltage levels are specified on an rms (root mean square) basis, and on the assumption that the waveform is a sine wave. For a sinusoidal waveform, the number of rms watts is calculated based on a voltage equal to 0.707 times the maximum ("peak") voltage that is reached by the waveform. So the word "peak" in that context means something different than the "maximum" power level corresponding to a musical "peak," which refers to rms power and not instantaneous peak power.
In other words, what would be most meaningful is to determine the maximum voltage level that is reached under worst case listening conditions, multiply that number by 0.707, and apply the E^2/R formula to the result. Applying the E^2/R formula to the maximum voltage level that is reached would work in the direction of making the amplifier seem more underpowered than it may actually be, by a factor of about 2.
Regards,
-- Al