As Kosst alluded to the question is somewhat unclear. But **if** you are asking what the difference in SPL would be on a per watt basis between an 8 ohm speaker rated at 97 db/2.83 volts/1 meter and a 6 ohm speaker rated at 97 db/2.83 volts/1 meter, and assuming those specs are accurate (which is often a bad assumption, as Erik indicated), the calculation would be as follows:
Power into a resistive load = Voltage squared/Resistance
Therefore:
2.83 volts into 8 ohms = (2.83 x 2.83)/8 = 1 watt
2.83 volts into 6 ohms = (2.83 x 2.83)/6 = 1.335 watts
The ratio of two amounts of power, expressed in db, is:
db = 10 x log(P1/P2), where "log" is the base 10 logarithm.
10 x log(1.335/1) = 1.25 db.
So if both speakers are provided with the same number of watts the 6 ohm speaker would produce an SPL that is 1.25 db lower than the SPL produced by the 8 ohm speaker, if both have sensitivities of 97 db/2.83 volts/1 meter.
Regards,
-- Al
Power into a resistive load = Voltage squared/Resistance
Therefore:
2.83 volts into 8 ohms = (2.83 x 2.83)/8 = 1 watt
2.83 volts into 6 ohms = (2.83 x 2.83)/6 = 1.335 watts
The ratio of two amounts of power, expressed in db, is:
db = 10 x log(P1/P2), where "log" is the base 10 logarithm.
10 x log(1.335/1) = 1.25 db.
So if both speakers are provided with the same number of watts the 6 ohm speaker would produce an SPL that is 1.25 db lower than the SPL produced by the 8 ohm speaker, if both have sensitivities of 97 db/2.83 volts/1 meter.
Regards,
-- Al