Bobby, it is my understanding that the mathematics involved in a second order filter dictate that, at the crossover point, you have one leg that has gone 90 degrees inductive and the other leg has gone 90 degrees capacitive. The two legs are 180 degrees out of phase; one is leading and one is lagging. If you wire the drivers in the same phase on both sides of that crossover, what you end up with is a null at the crossover frequency. You say you have no null and wire the drivers in phase.
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- 79 posts total
- 79 posts total