Ineed some help with a simple math equation


I have an amp with 29 dB gain with power output at 400, will this be bettered by an amp with 26 dB gain and 500 output? I'd like to have the extra 100 for my Thiel 3.6, which eat power like they are eating peanuts.
Thanks
Bill
bill10907
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Perceived loudness change can be calculated as:

k^(1/3.5)    where k is a ratio of powers.

(500/400)^(1/3.5) = 1.066  (6.6% increase).
I doubt that you can hear that.  

You want "better".  If you need more sensitivity you will be 2.03dB "better" with 29dB/400W
Better measurements IMHO are distortion and noise in the actual usable range. If you have spec sheets, look at the THD+N in the 30-100 W range.

However, inefficient speakers are less sensitive to noise, and many doubt we can hear anything below 0.5%, so absolute numbers below that may e meaningless.

Best,

E
Also important to understand how they eat power. Are they low impedance ? Difficult to drive due to high phase angle or low Z in the bass?

You may indeed need a very solid amp, but not necessarily need all those rated watts at 8 ohms.

Best,

E
As a Thiel 3.6 owner I wholeheartedly agree the more power the better (those speakers are excellent at high level transients, which is probably why they need power).

My suggestion: since the Thiels have an average impedance of less than three ohms from mid bass to 20khz, go with the amplifier that has the highest 4 ohm power rating at 1000 hz. (I assume those power specs are at 8 ohms).