@lostinseattle -
I'll try to explain it (ElectraClear) in general terms -
Consider the idea of a clock and dividing its rate or frequency into slower and slower rates. Now the clock has to be a fast rising edge, like a pulse, so as to trigger the dividing process. The outputs are square wave signals. What is a square wave? If you look up Fourier and his discovery of harmonics and transforms, you will learn that they are comprised of sine/cosine waves of a variety of related harmonics to the fundamental.
I presume that there is a situation that mirrors or reflects the pulsing action of a square wave onto the AC line however minute that may be.
This mechanism eludes me.But it must be something in the semiconductor transistor output or the small em field generated that allows this transfer. Not sure here.
Accepting this -
This is a pulsing event and not "ripple" but more of a defined square wave form of very small amplitude and lower in frequency(s) than 60 Hz. If this activity gets reflected onto the AC line then it is likely that it will not be filtered completely by power supply filters. What we're talking about is sine waves of a harmonic relationship extending to, mathematically speaking, infinity per Fourier. The frequencies of this harmonic series in the audio band will be present on the voltage reference, the DC voltage reference. This means that the DC line contains some harmonic information, albeit small. But small goes a long way.
An increase of 0.1 volt change from 1.0 v is 1.1 v and is equivalent to a gain of 0.83 dB.
Now the idea of resonance is vibrating at a similar or like frequency.
When this happens there is an energy transfer or increase in beats ala a tuning fork when in resonance with a like frequency.
Like that, the harmonic resonates with a similar or like frequencies in the audio amplifier. There are many harmonics in the square wave form so they too, will resonate with whatever frequency(s) come into the amp.
What you here will be an increase in harmonic information as the signal passes through the amplifier to speaker.
I'll try to explain it (ElectraClear) in general terms -
Consider the idea of a clock and dividing its rate or frequency into slower and slower rates. Now the clock has to be a fast rising edge, like a pulse, so as to trigger the dividing process. The outputs are square wave signals. What is a square wave? If you look up Fourier and his discovery of harmonics and transforms, you will learn that they are comprised of sine/cosine waves of a variety of related harmonics to the fundamental.
I presume that there is a situation that mirrors or reflects the pulsing action of a square wave onto the AC line however minute that may be.
This mechanism eludes me.But it must be something in the semiconductor transistor output or the small em field generated that allows this transfer. Not sure here.
Accepting this -
This is a pulsing event and not "ripple" but more of a defined square wave form of very small amplitude and lower in frequency(s) than 60 Hz. If this activity gets reflected onto the AC line then it is likely that it will not be filtered completely by power supply filters. What we're talking about is sine waves of a harmonic relationship extending to, mathematically speaking, infinity per Fourier. The frequencies of this harmonic series in the audio band will be present on the voltage reference, the DC voltage reference. This means that the DC line contains some harmonic information, albeit small. But small goes a long way.
An increase of 0.1 volt change from 1.0 v is 1.1 v and is equivalent to a gain of 0.83 dB.
Now the idea of resonance is vibrating at a similar or like frequency.
When this happens there is an energy transfer or increase in beats ala a tuning fork when in resonance with a like frequency.
Like that, the harmonic resonates with a similar or like frequencies in the audio amplifier. There are many harmonics in the square wave form so they too, will resonate with whatever frequency(s) come into the amp.
What you here will be an increase in harmonic information as the signal passes through the amplifier to speaker.