Sorry but your example is too simplistic to be realistic. That 10V drop assumes the capacitors never charge. They do of course.
As well if there was 1 ohm resistance the spikes would not longer be 10A since current would be limited by voltage drop across the resistor (see charged capacitors above).
How would this potential loss be audible in a "poorly regulated" amplifier? That would require you justifying that there would be more noise with higher resistance. You have not done that yet.
As well if there was 1 ohm resistance the spikes would not longer be 10A since current would be limited by voltage drop across the resistor (see charged capacitors above).
How would this potential loss be audible in a "poorly regulated" amplifier? That would require you justifying that there would be more noise with higher resistance. You have not done that yet.