Is my anti-skating too strong.

Justme, what I objected to in MC’s generalization was his saying “no overhang, no skating force”. I believe that is a direct quote from his post. The fact is that any pivoted tonearm, whether it overhangs the spindle or not will generate a skating force. The one exception is for in underhung tonearm, or a tonearm where the stylus does not reach the spindle. Such tonearms are built with zero head shell offset angle. In that case, when the stylus tip is at its single null point on the surface of an LP, for that instant only, there is no skating force. Everywhere else on the LP there is a skating force, even with an underhung tonearm. I don’t disagree that when you have the stylus overhang the spindle, per se that will cause a skating force. It’s the Pythagorean Theorem.

@lewm 

In fact all of our pivoted tonearms mounted so the stylus overhangs the spindle WILL generate a skating force even at the two null points, because of headshell offset angle. 

Not wishing to stretch this overwrought saga out, but this is not correct.
Skating forces are due to the offset headshell/cartridge AND the pull on the stylus.
At tangent the inward skating force is zero, and therefore at the 2 null points it is zero.

Justme, what I objected to in MC’s generalization was his saying “no overhang, no skating force”. I believe that is a direct quote from his post. The fact is that any pivoted tonearm, whether it overhangs the spindle or not will generate a skating force. 

NO NO NO WRONG WRONG WRONG! Actually worse than wrong, confused beyond recognition. Stop confusing everything!

Look lewm, you said spindle! The spindle has nothing to do with it! Skating forces are generated by the stylus not tracking tangentially.

Look, forget pivoted arms for a second. Think about tangential tracking arms.

Do you at least understand that a tangential tracking arm has no skating force to contend with? Because it is tangent. Perfectly perpendicular to the groove at the point of contact. Because when perfectly perpendicular the force is perfectly parallel to the arm and there is no skating force. Do you at least understand that much? 

This is a complex topic, whether you like it or not. It seems that when I focus on one aspect, you assail me for not focusing on another aspect.  So this is useless.   I did NOT ever say the "spindle" caused the skating force, for god's sake.  When we use the term "overhang" we are referring to pivoted tonearms that are set up such that the stylus tip overhangs the spindle.  I mentioned the spindle for the benefit of anyone who might be trying to follow the logic or who might not be familiar with the meaning of "overhang". That is the context in which I used the word "spindle".  I would like to add with respect to your last post, that when I first discussed the mechanism of the skating force, you got after me for talking in terms of the cantilever and not mentioning the rest of the tonearm system.  Now here you can  be caught out for talking about the stylus alone.  The stylus can be thought of as a single point on the surface of the LP.  As such, the "stylus" can never be tangent to anything.  For tangency, you need two objects that have at least 2-dimensionality.  The point in space has only one.  The cantilever, on the other hand, can be thought of as a straight line, which can exhibit tangency to a circle (the LP groove).  I believe you understand this topic almost as well as I do. Why do you need to include ridicule in your rejoinders? 

@dover 

Not wishing to stretch this overwrought saga out, but this is not correct.Skating forces are due to the offset headshell/cartridge AND the pull on the stylus.At tangent the inward skating force is zero, and therefore at the 2 null points it is zero

How can this be true?  When the stylus is tangent to the groove (null point) the pulling force caused by the friction with be inline with the tonearm’s linear offset, thereby causing a rotational torque around the tonearm’s pivot.  Only a zero offset underslung tonearm will exhibit zero skating at the null point as Lewn has pointed out numerous times