Andy2, there are no contradictions, I’m trying to explain to you a simple thing that is understandable even to a schoolboy. This is getting ridiculous, by God.
You wrote:
Of course if optimized then it may sound different. During playback, the audio file has to be "decompressed" or if you will "processed" by the CPU. Therefore it will have its own digital interference signature which will affect the DAC clock.
OK. Imagine that we have an original file (A), an optimized file (B) that is PHYSICALLY identical to A, and an ordinary digital copy of the file (C) that is PHYSICALLY identical to A, all located on the same disk. Then:
By the sound: A ≈ C ≠ B.
In the digit: A = C = B
At the same time, you claim that A sounds different from B because A is not physically equal to B since the files have "its own digital interference signature". This in itself is nonsense, but let’s assume that it is.
Then answer the question:
Why then is the sound A ≈ C? In other words, how can normal copying differ from optimization if in both cases we always have files with the same checksum at the output?
Keep in mind that if we do re-optimization (B1, B2, B3...) and re-copying (C1, C2, C3...), we have:
By sound: A ≈ C ≈ C1 ≈ C3 ≈ Cn ≠ B ≠ B1 ≠ B2 ≠ B3 ≠ Bn
In digit: A = C = C1 = C2 = C3 = Cn = B = B1 = B2 = B3 = Bn
So answer the question please, then we’ll see who is schizophrenic and who is just stupid.