Ohm question


OK, first off, I doubt i would ever try this, but i was just curious about something and thought i would get everyones take on this.

Bear with me now, im a little rusty on electronic formulas, and i might have this bass ackwards.

Basic understanding of electronics dictates that if you have 2 10ohm loads and wire them up in series you have a 20 ohm load right?

And if you have 2 10ohm loads, and wire them up in parallel, you get a 5ohm load right?

So, if you stack 2 4ohm speakers, what impact would you see as a result of wiring them in series to create a 8 ohm load?

How would it impact sonics?
Amperage?
Wattage?
slappy
The question of mixing speakers in parallel comes up so often and the formula is so simple that everyone should memorize it or jot it down:

R1 X R2 "R" is the speaker impedence in ohms. If the
------- Speakers were 8 ohm and 6 ohm it would be 8 X 6
R1 + R2 = 48 divided by 8 + 6 = 14 for an answer of
3.43

Write it down. Really. You'll need it sometime in the future.
uhm....
that is not the quetion i asked Elgordo, i was curious about wattage and current, and any adverse audible affects on the speakers.

im not even talking about mixing speakers, im talking about identical speakers, and it looks like my math already was correct.

Thanks though
One of the best stereo demonstrations I ever heard was in the home of a DIY musician in France who had removed the internal resistors on 2 pairs of Quad ESL speakers and had them wired in series for the left and right channels.
For your specific question, I would suggest to simply contact Magnapan.